Answer with explanation:
The equation of line is, y= -x +3
→x+y-3=0---------(1)
⇒Equation of line Parallel to Line , ax +by +c=0 is given by, ax + by +K=0.
Equation of Line Parallel to Line 1 is
x+y+k=0
The Line passes through , (-5,6).
→ -5+6+k=0
→ k+1=0
→k= -1
So, equation of Line Parallel to line 1 is
x+y-1=0
⇒Equation of line Perpendicular to Line , ax +by +c=0 is given by, bx - a y +K=0.
Equation of Line Perpendicular to Line 1 is
x-y+k=0
The Line passes through , (-5,6).
→ -5-6+k=0
→ k-11=0
→k= 11
So, equation of Line Parallel to line 1 is
x-y+11=0
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