Answer:
162, 163, and 164.
Step-by-step explanation:
Here we will use algebra to find three consecutive integers whose sum is 489. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 489. Therefore, you can write the equation as follows:
(X) + (X + 1) + (X + 2) = 489
To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:
X + X + 1 + X + 2 = 489
3X + 3 = 489
3X + 3 - 3 = 489 - 3
3X = 486
3X/3 = 486/3
X = 162
Which means that the first number is 162, the second number is 162 + 1 and the third number is 162 + 2. Therefore, three consecutive integers that add up to 489 are 162, 163, and 164.
162 + 163 + 164 = 489
We know our answer is correct because 162 + 163 + 164 equals 489 as displayed above.
Answer:
Step-by-step explanation:
Round to 2 inches
A = π(2²) = 4π = 4(3.14) = 12.56 in²
A = π(2.43²) = 18.541386 ≈ 18.54 in²
S+m+l=28
4s+2m+l=58
6s+5m+4l=135
Eliminate the variable l from the first 2 equations
s+m+l=28
-4s-2m-l=-58
-3s-m=-30
Elminiate the variable l from the last 2 equations
6s+5m+4l=135
-16s-8m-4l=-232
-10s-3m=-97
Now solve for s and m using the 2 equations without l
-3s-m=-30
-10s-3m=-97
9s+3m=90
-10s-3m=-97
-s=-7
s=7
Then plug in s into one of the equations without l
-3(7)-m=-30
-21-m=-30
-m=-9
m=9
Now plus in s and m into one of the original 3 equations
(7)+(9)+l=28
16+l=28
l=12
Final answer:
Small=$7
Medium=$9
Large=$12
I know it only asks for large but I wanted to show you how to find them all for future reference. :)
Answer:
it is C. or A.
Step-by-step explanation:
hope i help