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3 years ago

What is a linear system?

Mathematics

2 answers:

Darya [45]3 years ago

8 0

Answer:

Linear systems are systems of equations in which the variables are never multiplied with each other but only with constants and then summed up

Darya [45]3 years ago

4 0

Answer:

$\huge \underline\bold\red{Answer}$

Step-by-step explanation:✏ Linear systems are systems of equations in which the variables are never multiplied with each other but only with constants and then summed up.

For example, the propagation medium for wireless communication systems can often be modeled by linear systems...!

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WILL GIVE BRAINLIEST

sdas [7]

3. f(-6) = 12+1 =13

f(-2) = 4+1 = 5

f(0) =1

Range {1,5,13}

4. f(-2) = (-2)^3+1 =-7

f(-1) = (-1)^2 +1 =0

f(3) = (3)^3 +1 = 28

Range = {-7,0,28}

5.the sequence is arithmetic

d= -11+19 = 8

an = a1 + d(n-1)

an = -19 +8(n-1)

6.l =w+5

a =l*w

a(w) =(w+5) * w

a(w)= w^2 +5w

f(w) = w^2 +5w

f(8) = 8^2 +5(8)

f(8) = 64 +40

f(8) =104 in^2

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3 years ago

Please help with this algebra

scoray [572]

Answer:

Step-by-step explanation:

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7 0

2 years ago

Can anyone help me in dis pls

Varvara68 [4.7K]

Answer:

Step-by-step explanation:

a^2 + b^2 = C^2

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b^2 = c^2 - a^2

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3 years ago

What is 1/10 of 12.5 miles?

vazorg [7]

Answer:

1.25

Step-by-step explanation:

(1/10) x 12.5

4 0

3 years ago

Measure the lengths of the sides of ∆ABC in GeoGebra, and compute the sine and the cosine of ∠A and ∠B. Verify your calculations

marusya05 [52]

Answer:

$Sin \angle A =0.80$

$Cos \angle A=0.60$

$Sin \angle B =0.60$

$Cos \angle B=0.80$

Step-by-step explanation:

Given

I will answer this question using the attached triangle

Solving (a): Sine and Cosine A

In trigonometry:

$Sin \theta =\frac{Opposite}{Hypotenuse}$ and

$Cos \theta =\frac{Adjacent}{Hypotenuse}$

So:

$Sin \angle A =\frac{BC}{BA}$

Substitute values for BC and BA

$Sin \angle A =\frac{8cm}{10cm}$

$Sin \angle A =\frac{8}{10}$

$Sin \angle A =0.80$

$Cos \angle A=\frac{AC}{BA}$

Substitute values for AC and BA

$Cos \angle A=\frac{6cm}{10cm}$

$Cos \angle A=\frac{6}{10}$

$Cos \angle A=0.60$

Solving (b): Sine and Cosine B

In trigonometry:

$Sin \theta =\frac{Opposite}{Hypotenuse}$ and

$Cos \theta =\frac{Adjacent}{Hypotenuse}$

So:

$Sin \angle B =\frac{AC}{BA}$

Substitute values for AC and BA

$Sin \angle B =\frac{6cm}{10cm}$

$Sin \angle B =\frac{6}{10}$

$Sin \angle B =0.60$

$Cos \angle B=\frac{BC}{BA}$

Substitute values for BC and BA

$Cos \angle B=\frac{8cm}{10cm}$

$Cos \angle B=\frac{8}{10}$

$Cos \angle B=0.80$

Using a calculator:

$A = 53^{\circ}$

So:

$Sin(53^{\circ}) =0.7986$

$Sin(53^{\circ}) =0.80$ -- approximated

$Cos(53^{\circ}) = 0.6018$

$Cos(53^{\circ}) = 0.60$ -- approximated

$B = 37^{\circ}$

So:

$Sin(37^{\circ}) = 0.6018$

$Sin(37^{\circ}) = 0.60$ --- approximated

$Cos(37^{\circ}) = 0.7986$

$Cos(37^{\circ}) = 0.80$ --- approximated

8 0

2 years ago

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