Find an equation equivalent to r= 1 + 2 sin thete in rectangular coordinates
1 answer:
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Step-by-step explanation:
Take the first derivative
Set the derivative equal to 0.
or
For any number less than -1, the derivative function will have a Positve number thus a Positve slope for f(x).
For any number, between -1 and 1, the derivative slope will have a negative , thus a negative slope.
Since we are going to Positve to negative slope, we have a local max at x=-1
Plug in -1 for x into the original function
So the local max is 2 and occurs at x=-1,
For any number greater than 1, we have a Positve number for the derivative function we have a Positve slope.
Since we are going to decreasing to increasing, we have minimum at x=1,
Plug in 1 for x into original function
So the local min occurs at -2, at x=1
Answer:
Option B. No, because the graph of the line connecting the ordered pairs does no pass through the origin.
Step-by-step explanation:
we know that
A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form or
In a proportional relationship the constant of proportionality k is equal to the slope m of the line<u><em> and the line passes through the origin</em></u>
step 1
Connect the ordered pairs of the graph
The y-intercept is the point (0,20)
see the attached figure
That means, that the line not passes through the origin
therefore
The relationship between the two quantities is not proportional
