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Naddika [18.5K]
3 years ago
9

Find the value of each variable in the parallelogram

Mathematics
1 answer:
kompoz [17]3 years ago
4 0

9514 1404 393

Answer:

  k = 7

  m = 8

Step-by-step explanation:

The diagonals bisect each other, so each half is equal to the opposite half.

  k +4 = 11 . . . . down-sloping diagonal

  k = 7

__

  m = 8 . . . . up-sloping diagonal

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Which bacteria sample (A or B) had a smaller initial population? What was that value?
zubka84 [21]

Answer:

B has a smaller initial population of 500

Step-by-step explanation:

Given

See attachment for complete question

Required

The bacteria with the smaller initial population

The initial population is at x = 0

For bacteria A;

A(x) = 600 when x = 0

For bacteria B, we have:

B(x) = 500(2)^x

Substitute 0 for x

B(x) = 500(2)^0

B(x) = 500*1

B(x) = 500

So; when x = 0

A(x) = 600 and B(x) = 500

Because; 500 < 600

We can conclude that B has a smaller initial population of 500

4 0
2 years ago
Shelia is dividing x4 – 4x3 + 4x2 – 6x + 5 by x – 1 using a division table. Quotient Divisor x3 – 3x2 + x – 5 x x4 –3x3 x2 A – 1
Hatshy [7]
Is there by answer choice? Or by a table?
4 0
3 years ago
To pass a test 36% marks are needed out of maximum a student gets 123 marks and is declared failed by 39 marks what are maximum
IgorLugansk [536]

If the student got 123 marks and failed by 39, your first step would be to add the two together, getting 162. This is the amount of marks needed to pass the test.

You would then divide 162 by .36 (.36 is equivalent to 36%). This would result in a maximum of 450 marks.

The maximum marks on this test are 450 marks.

8 0
3 years ago
The length of a rectangle is 4 less than 2 times the width. The perimeter is 40 units.
bezimeni [28]

Answer:

Let l be length and w be width.

First equation:

l = 2w-4

Second equation:

perimeter = 40 units

Perimeter of a rectangle: 2(l+w)

2(2w-4+w)=40

2(3w-4)=40

6w-8=40

6w=40+8

6w=48

w=48/6

w=8

Therefore the width=8;

length= 2w-4 = 2(8)-4  = 16-4  = 12

perimeter = 40 units

8 0
3 years ago
__________We can be 99% confident that the true percentage of U.S. adults Twitter users who get some news through Twitter is bet
irakobra [83]

First part of question states;

A poll conducted in 2013 found that the proportion of of U.S. adult Twitter users who get at least some news on Twitter was 0.52 The standard error for this estimate was 0.024, and a normal distribution may be used to model the sample proportion.

Answer:

<u>True</u>

<u>Step-by-step explanation:</u>

From the statement above and after constructing the 99% confidence interval for the proportion of U.S. adult Twitter users we can infer that the 95% confidence upper and lower bounds are 0.52 and 0.79, which means that there's a 99% confident that the true percentage of U.S. adults Twitter users who get some news through Twitter is between the upper and lower bounds of the confidence interval.

7 0
3 years ago
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