Question

What's the inverse of ƒ(x) = x2 – 16?

Answer 1

the inverse of ƒ(x) = x²– 16

${f}^{ - 1} (x) = \sqrt{x + 16}$

Answer 2

Answer:

The inverse function should be f

${f}^{ - 1}( x) = \sqrt{x + 16}$

this is the correct answer