For the first question, simply make a right angle triangle with the following dimensions.
The angle of elevation or the angle from the ground between the first floor and ground is 60 degrees.
The height between the 2 floors is 26 feet.
Solve for the hypotenuse, or the diagonal length between the first and second floors.
Then for the second question, divide the length in feet by the rate to find the time it takes for the object to move.
3 is the lesser and 4 is the higher, because taking away 1 from four is 25%.
Answer:
-22
Step-by-step explanation:
given= 0
lost= -8 times 3 = -24
won= 4 -24+4=-20
lost= -2 -20-2=-22
Answer=-22
Answer:
The ship is located at (3,5)
Explanation:
In the first test, the equation of the position was:
5x² - y² = 20 ...........> equation I
In the second test, the equation of the position was:
y² - 2x² = 7 ..............> equation II
This equation can be rewritten as:
y² = 2x² + 7 ............> equation III
Since the ship did not move in the duration between the two tests, therefore, the position of the ship is the same in the two tests which means that:
equation I = equation II
To get the position of the ship, we will simply need to solve equation I and equation II simultaneously and get their solution.
Substitute with equation III in equation I to solve for x as follows:
5x²-y² = 20
5x² - (2x²+7) = 20
5x² - 2y² - 7 = 20
3x² = 27
x² = 9
x = <span>± </span>√9
We are given that the ship lies in the first quadrant. This means that both its x and y coordinates are positive. This means that:
x = √9 = 3
Substitute with x in equation III to get y as follows:
y² = 2x² + 7
y² = 2(3)² + 7
y = 18 + 7
y = 25
y = +√25
y = 5
Based on the above, the position of the ship is (3,5).
Hope this helps :)
