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levacccp [35]
3 years ago
6

Which diagram shows the product 36 x 2.05?

Mathematics
1 answer:
cricket20 [7]3 years ago
4 0
C is the answer because you must multiply the length and the width which is 2+.0.05 = 2.05 and 36. 2.05 x 36
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A recipe use 5 cups of flour for every 2 cups of sugar .a.how much sugar is used for 1 cup of flour? b.how much flour is used fo
zheka24 [161]

Answer:

1 cup of sugar per 2.5 cups of flour.

2.5 cups of flower per 1 cup of sugar.

17.5 cups of flower is used with 7 cups of sugar.

1.6 cups of sugar is used with 6 cups of flour.

Step-by-step explanation:

5 0
3 years ago
If y=e5t is a solution to the differential equation
a_sh-v [17]

Answer:

k = 30, y(t) = C_1e^{5t}+C_2e^{6t}

Step-by-step explanation:

Since y=e^{5t} is a solution, then it must satisfy the differential equation. So, we calculate the derivatives and replace the value in the equation. We have that

\frac{d^2y}{dt^2} = 25 e^{5t},\frac{dy}{dt} = 5e^{5t}

Then, replacing the derivatives in the equation we have:

25e^{5t}-11(5)e^{5t}+ke^{5t}=0 e^{5t}(25-55+k) =0

Since e^{5t} is a positive function, we have that

25-55+k = 0 \rightarrow k = 30.

Now, consider a general solution y(t) = Ae^{rt}, A \in \mathbb{R}, then, by calculating the derivatives and replacing them in the equation, we get

Ae^{rt}(r^2-11r+30)=0

We already know that r=5 is a solution of the equation, then we can divide the polynomial by the factor (r-5) to the get the other solution. If we do so, we get that (r-6)=0. So the other solution is r=6.

Therefore, the general solution is

y(t) = C_1e^{5t}+C_2e^{6t}

8 0
3 years ago
Write an expression showing 5 less than the number K
BigorU [14]

Answer:

k-5

Step-by-step explanation:

5 0
2 years ago
How do I solve this question?
Yuri [45]
It's 18/100. The reduced / simplest form is 9/50 because you divide it by 2 since it's the GCS.
4 0
2 years ago
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A 52 foot ladder is set against the side of a house so that it reaches up 48 feet. If Jace
Alik [6]

Answer:

34.3

Step-by-step explanation:

no

8 0
3 years ago
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