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3 years ago

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Joe has 16 pounds of fertilizer for his three gardens. He uses 8/3 of the fertilizer in his first garden and 1/4 of the fertiliz

er in his second garden. What fraction of the fertilizer is left for the third garden?

1 answer:

Natasha2012 [34]3 years ago

3 0

Answer:

3/8

Step-by-step explanation:

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Plz help what is the answer for this question?

Liula [17]

Answer:

Step-by-step explanation:

THE ANSWER IS C

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2 years ago

Read 2 more answers

IV. Intercepts. Give the intercepts of the following linear equations. 1) 5x + 3y = 8 2) 10x + 6y - 12 = 4 3) 2x – 3y = 5 4) 3x

rosijanka [135]

Answer:

1) $\frac{8}{3}$

2) $\frac{8}{3}$

3) $\frac{-5}{3}$

4)2

Step-by-step explanation:

1) 5x + 3y = 8

3y=8-5x

$y=\frac{-5}{8} x+\frac{8}{3}$

hence intercept is $\frac{8}{3}$

2) 10x + 6y - 12 = 4

10x + 6y = 16

6y=16-10x

$y=\frac{-10}{6} x+\frac{16}{6}$

hence intercept is $\frac{8}{3}$

3) 2x – 3y = 5

3y=2x-5

$y=\frac{2}{3} x+\frac{-5}{3}$

hence intercept is $\frac{-5}{3}$

4) 3x + 2y = 1

2y=-3x+4

$y=\frac{-3}{2} x+\frac{4}{2}$

hence intercept is 2

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3 years ago

Which is equivalent to the following expression (3m^2+2mn-n^2)+(m^2+4mn-n^2)

olga2289 [7]

Answer:

<h3>4m² + 6mn - 2n²</h3>

Step-by-step explanation:

$(3m^2+2mn-n^2)+(m^2+4mn-n^2)\\\\=3m^2+2mn-n^2+m^2+4mn-n^2\qquad\text{combine like terms}\\\\=(3m^2+m^2)+(2mn+4mn)+(-n^2-n^2)\\\\=\boxed{4m^2+6mn-2n^2}$

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Answer:

I think C.

Step-by-step explanation:

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