Answer:
yes above statement is true
Step-by-step explanation:
mark me as brainliest ❤️
Answer:
D
Step-by-step explanation:
x/(x²+3x+2) - 1/[(x+2)(x+1)]
x² + 3x + 2 = x² + 2x + x + 2
= x(x + 2) + (x + 2)
= (x + 2)(x + 1)
= x/[(x+2)(x+1)] - 1/[(x+2)(x+1)]
= (x-1)/[(x+2)(x+1)]
= (x-1)/(x²+3x+2)

This result is actually true for any exterior angle. The exterior angle of a triangle is equal to the sum of the two remote angles, and above is a short proof of it.
Answer:
P = 70 mi A = 210 mi^2
Step-by-step explanation:
Sides:
a = 29 m
b = 20 m
c = 21 m
Angles:
A = 90 °
B = 43.6028 °
C = 46.3972 °
Other:
P = 70 m
s = 35 m
K = 210 mi^2
r = 6 m
R = 14.5 m
Agenda:
A = angle A
B = angle B
C = angle C
a = side a
b = side b
c = side c
P = perimeter
s = semi-perimeter
K = area
r = radius of inscribed circle
R = radius of circumscribed circle
SSS is Side, Side, Side
Heron’s formula says that if a triangle ABC has sides of lengths a, b, and c opposite the respective angles, and you let the semiperimeter, s, represent half of the triangle’s perimeter, then the area of the triangle is