The amount of heat released when 12.0g of helium gas condense at 2.17 K is; -250 J
The latent heat of vapourization of a substance is the amount of heat required to effect a change of state of the substance from liquid to gaseous state.
However, since we are required to determine heat released when the helium gas condenses.
The heat of condensation per gram is; -21 J/g.
Therefore, for 12grams, the heat of condensation released is; 12 × -21 = -252 J.
Approximately, -250J.
Read more on latent heat:
brainly.com/question/19863536
Answer:
The slope is .075 and the y intercept is -.125
Step-by-step explanation:
8y = .2(3x -5)
Distribute the .2
8y = .6x - 1
Divide by 8
8y/8 = .6x/8 -1/8
y = .075x -.125
This is in slope intercept form y= mx+b where m is the slope and b is the y intercept.
The slope is .075 and the y intercept is -.125
The angle VXU is larger than a 90 degree angle half of an exact straight angle (180 degrees) so it’s obtuse. The only angle larger 90 degree is D :)
The answer is 90,000.
The value of 9 in 495,123 is 10,000 times the value of 9 in 63,129
Answer:
C. √5
Step-by-step explanation:
