The table is:0 1 2 3
x1 0 0.08 0.06 0.04 0.00
1 0.05 0.18 0.05 0.03
2 0.05 0.04 0.10 0.06
3 0.00 0.03 0.04 0.07
4 0.00 0.01 0.05 0.06
Expected difference =
+(0.08*(0-0)) +(0.06*(0-1)) +(0.04*(0-2)) +(0.00*(0-3)) +(0.05*(1-0)) +(0.18*(1-1)) +(0.05*(1-2)) +(0.03*(1-3)) +(0.05*(2-0)) +(0.04*(2-1)) +(0.10*(2-2)) +(0.06*(2-3)) +(0.00*(3-0)) +(0.03*(3-1)) +(0.04*(3-2)) +(0.07*(3-3)) +(0.00*(4-0)) +(0.01*(4-1)) +(0.05*(4-2)) +(0.06*(4-3))
= 0.17
Answer:
It would be the first one honey :)
Step-by-step explanation:
Answer:
7.3
Step-by-step explanation:
For this question, you must use the distance formula. The distance formula is based around Pythagorean Theorem, so you will see some similarities.
Distance = 
X2 is 7 (X coordinate of school)
X1 is 5 (X coordinate of friend's house)
7 - 5 = 2
2^2 = 4
Y2 is 7 (Y coordinate of school)
Y1 is 0 (Y coordinate of friend's house)
7 - 0 = 7
7^2 = 49
4 + 49 = 53
= 7.2801...
<em>Round to the nearest tenth...</em>
<em>7.3</em>
First, you have to find the median, which is the number in the middle: 25
Then cut the data in half by the median, so your new data sets are
15,29,20
and
31,38,41
Now you find the median of both of those sets, which is 29 and 38.
The interquartile range is the difference between the numbers, so 38-29 = 9.
There is not enough information
