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jeyben [28]
3 years ago
11

Help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
garik1379 [7]3 years ago
4 0

B is true. This my answer

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What is the area of the composite figure? -70 cm2 -100 cm2 -105 cm2 -130 cm2
mr Goodwill [35]

Make two shapes out of it.

The bottom is a rectangle 14 x 5 = 70 square cm

The top is a triangle 1/2 x 12 x 5 = 30 square cm

Total area = 70 + 30 = 100 square cm

4 0
3 years ago
Read 2 more answers
The sum of three consecutive odd numbers is 51. Find the numbers. Show your work and
Pachacha [2.7K]
15,17,19 are all odd numbers and add to 51
4 0
3 years ago
Geometry question. please help ​
Vinvika [58]

Answer:

The length of PQ is <u>18</u> feet.

The length of PR is <u>18</u> feet.

The length of QR is <u>24</u> feet.

Step-by-step explanation:

A way to set an equation up for this problem is:

\frac{4}{3}x+x+x=60

where x is the three lengths of the isosceles triangle, but the base QR is 4/3 the length of the other two congruent sides, length PQ and PR. The 60 represents the total length of the perimeter.

Then, solve for x from the equation, and you’ll get x=18. But your not done yet. Since the variable x in the equation stands for the sides of the isosceles triangle, so plug 18 into the equation and it should look like this:

\frac{4}{3}(18)+18+18=60

Don’t solve the whole equation, just solve the \frac{4}{3}(18) part of the equation, which is equal to 24. So the final equation is this:

24+18+18=60

Conclusion: 24 is the length of QR, and 18 is the length of PQ and PR. And they all equal 60, which is the perimeter. This is very true because the length of PQ and PR are the same (length 18), since it’s an isosceles triangle, and the length of QR is 4/3 the length of PQ and PR (4/3 of 18= 24).

Sorry for the long explanation.

But hope this helps and answers your question :)

8 0
3 years ago
Lori entered a 100 km race. A Kilometer is about of a mile. About how many miles ling is the race?
djverab [1.8K]

Answer:

About 62.1371

Step-by-step explanation:

6 0
3 years ago
Can someone help me with this page?
Roman55 [17]
Sure
i will help with the page if i can do it…

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3 years ago
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