Question

Need help once again!

Answer 1

Answer:

θ = cos-1 (38/47)

Step-by-step explanation:

sin θ = $\frac{opposite}{hypotenuse} = \frac{27}{47}$

θ = sin-1 (27/47)

cos θ = $\frac{adjacent}{hypotenuse} = \frac{38}{47}$

θ = cos-1 (38/47)

tan θ = $\frac{opposite}{adjacent} = \frac{27}{38}$

θ = tan-1 (27/38)