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Alexxandr [17]
2 years ago
8

5. Is a parallelogram but not a rectangle

Mathematics
1 answer:
lakkis [162]2 years ago
6 0

Answer:

Yes

Step-by-step explanation:

All rectangles are parallelograms, but not all parallelograms are rectangles.

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Mai has a jar of quarters and dimes. She takes at least 10 coins out of the jar and has less than $2.00.
Rama09 [41]

Answer:

?

Step-by-step explanation:

Problem 1

Sketch or describe the figure in Step 4 and Step 15.

Pattern of small squares. Step 1 has 1 square. Step 2 has 4 squares, 2 by 2 with bottom left square moved to top right corner. Step 3 has 9 squares, 3 by 3 with bottom left moved to top right corner.

How many small squares will there be in each of these steps?

Write an equation to represent the relationship between the step number, , and the number of small squares, , in each step.

Explain how your equation relates to the pattern.

Problem 2

Which expression represents the relationship between the step number  and the total number of small squares in the pattern?

A pattern of small squares. Step 1 has 0 squares. Step 3 has 3 squares: 2 by 2 but missing the lower right square. Step 3 has 8 squares: 3 by 3 but missing the lower right square.

A:

B:

C:

D:

Problem 3

Each figure is composed of large squares and small squares. The side length of the large square is . Write an expression for the area of the shaded part of each figure.

Figure A

Large square with 1 by 1 small squares removed from each corner.

Figure B

2 large squares side by side. On the side of the right square, there are 2 small squares stacked vertically, each with dimensions 2 by 2.

Problem 4

Here are a few pairs of positive numbers whose difference is 5.

Find the product of each pair of numbers. Then, plot some points to show the relationship between the first number and the product.

first

number second

number product

1 6  

2 7  

3 8  

5 10  

7 12  

Blank coordinate plane. Horizontal axis, first number, 0 to 10. Vertical axis, product, 0 to 100 by 10s.

Is the relationship between the first number and the product exponential? Explain how you know.

(From Algebra1, Unit 6, Lesson 1.)

Problem 5

Here are some lengths and widths of a rectangle whose perimeter is 20 meters.

Complete the table. What do you notice about the areas?

length

(meters) width

(meters) area

(square meters)

1 9  

3 7  

5    

7    

9    

Without calculating, predict whether the area of the rectangle will be greater or less than 25 square meters if the length is 5.25 meters.

On the coordinate plane, plot the points for length and area from your table.

Do the values change in a linear way? Do they change in an exponential way?

A blank graph, origin O, with a grid.

Problem 6

Here is a pattern of dots.

Four figures, labeled step 0 through 3. Step 0, row with 1 dot. Step 1, row with 2 dots. Step 2, row with 2 dots above row with 3 dots. Step 3, 2 rows of 3 dots above row with 4 dots.

Complete the table.

How many dots will there be in Step 10?

How many dots will there be in Step ?

step total number

of dots

0  

1  

2  

3  (From Algebra1, Unit 6, Lesson 2.)

Problem 7

Mai has a jar of quarters and dimes. She takes at least 10 coins out of the jar and has less than $2.00.

Write a system of inequalities that represents the number of quarters, , and the number of dimes, , that Mai could have.

Is it possible that Mai has each of the following combinations of coins? If so, explain or show how you know. If not, state which constraint—the amount of money or the number of coins—it does not meet.

3 quarters and 12 dimes

4 quarters and 10 dimes

2 quarters and 5 dimes

(From Algebra1, Unit 2, Lesson 25.)

Problem 8

A stadium can seat 63,026 people. For each game, the amount of money that the organization brings in through ticket sales is a function of the number of people, , in attendance.

If each ticket costs $30.00, find the domain and range of this function.

6 0
3 years ago
What's the sum of 6+y
Elis [28]

Answer:

6y?

It's probably wrong but off the top of my head, 6y

4 0
3 years ago
You sell soup mixes for a fundraiser. For each soup mix you sell, the company that makes the soup receives x dollars l, and you
Whitepunk [10]

Answer: $ 6

Step-by-step explanation:

Here, the cost price of each soup = x dollars

The cost price of 16 soup = 16 x

The selling price of 16 soup = 16 x + 96

Since, the total money received for 16 soup = The selling price of 16 soup - The cost price of 16 soup

= 16 x + 96 - 16 x

= 96

Thus, the total money received for 16 soup = 96 dollars

⇒ The total money received for 1 soup = \frac{96}{16} dollars

⇒ The total money received for 1 soup = 6 dollars

Hence, for each soup 6 dollars is received.

7 0
3 years ago
Help me solve this plz
Reptile [31]

Answer:

sorry but this photo is not clear

8 0
3 years ago
Find the mass and center of mass of the lamina that occupies the region D and has the given density function rho. D is the trian
Alla [95]

Answer: mass (m) = 4 kg

              center of mass coordinate: (15.75,4.5)

Step-by-step explanation: As a surface, a lamina has 2 dimensions (x,y) and a density function.

The region D is shown in the attachment.

From the image of the triangle, lamina is limited at x-axis: 0≤x≤2

At y-axis, it is limited by the lines formed between (0,0) and (2,1) and (2,1) and (0.3):

<u>Points (0,0) and (2,1):</u>

y = \frac{1-0}{2-0}(x-0)

y = \frac{x}{2}

<u>Points (2,1) and (0,3):</u>

y = \frac{3-1}{0-2}(x-0) + 3

y = -x + 3

Now, find total mass, which is given by the formula:

m = \int\limits^a_b {\int\limits^a_b {\rho(x,y)} \, dA }

Calculating for the limits above:

m = \int\limits^2_0 {\int\limits^a_\frac{x}{2}  {2(x+y)} \, dy \, dx  }

where a = -x+3

m = 2.\int\limits^2_0 {\int\limits^a_\frac{x}{2}  {(xy+\frac{y^{2}}{2} )} \, dx  }

m = 2.\int\limits^2_0 {(-x^{2}-\frac{x^{2}}{2}+3x )} \, dx  }

m = 2.\int\limits^2_0 {(\frac{-3x^{2}}{2}+3x)} \, dx  }

m = 2.(\frac{-3.2^{2}}{2}+3.2-0)

m = 2(-4+6)

m = 4

<u>Mass of the lamina that occupies region D is 4.</u>

<u />

Center of mass is the point of gravity of an object if it is in an uniform gravitational field. For the lamina, or any other 2 dimensional object, center of mass is calculated by:

M_{x} = \int\limits^a_b {\int\limits^a_b {y.\rho(x,y)} \, dA }

M_{y} = \int\limits^a_b {\int\limits^a_b {x.\rho(x,y)} \, dA }

M_{x} and M_{y} are moments of the lamina about x-axis and y-axis, respectively.

Calculating moments:

For moment about x-axis:

M_{x} = \int\limits^a_b {\int\limits^a_b {y.\rho(x,y)} \, dA }

M_{x} = \int\limits^2_0 {\int\limits^a_\frac{x}{2}  {2.y.(x+y)} \, dy\, dx }

M_{x} = 2\int\limits^2_0 {\int\limits^a_\frac{x}{2}  {y.x+y^{2}} \, dy\, dx }

M_{x} = 2\int\limits^2_0 { ({\frac{y^{2}x}{2}+\frac{y^{3}}{3})}\, dx }

M_{x} = 2\int\limits^2_0 { ({\frac{x(-x+3)^{2}}{2}+\frac{(-x+3)^{3}}{3} -\frac{x^{3}}{8}-\frac{x^{3}}{24}  )}\, dx }

M_{x} = 2.(\frac{-9.x^{2}}{4}+9x)

M_{x} = 2.(\frac{-9.2^{2}}{4}+9.2)

M_{x} = 18

Now to find the x-coordinate:

x = \frac{M_{y}}{m}

x = \frac{63}{4}

x = 15.75

For moment about the y-axis:

M_{y} = \int\limits^2_0 {\int\limits^a_\frac{x}{2}  {2x.(x+y))} \, dy\,dx }

M_{y} = 2.\int\limits^2_0 {\int\limits^a_\frac{x}{2}  {x^{2}+yx} \, dy\,dx }

M_{y} = 2.\int\limits^2_0 {y.x^{2}+x.{\frac{y^{2}}{2} } } \,dx }

M_{y} = 2.\int\limits^2_0 {x^{2}.(-x+3)+\frac{x.(-x+3)^{2}}{2} - {\frac{x^{3}}{2}-\frac{x^{3}}{8}  } } \,dx }

M_{y} = 2.\int\limits^2_0 {\frac{-9x^3}{8}+\frac{9x}{2}   } \,dx }

M_{y} = 2.({\frac{-9x^4}{32}+9x^{2})

M_{y} = 2.({\frac{-9.2^4}{32}+9.2^{2}-0)

M{y} = 63

To find y-coordinate:

y = \frac{M_{x}}{m}

y = \frac{18}{4}

y = 4.5

<u>Center mass coordinates for the lamina are (15.75,4.5)</u>

3 0
3 years ago
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