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2 years ago

PLEASE HELP ME WITH THIS QUESTION

Mathematics

1 answer:

shusha [124]2 years ago

7 0

Answer:

66°

Step-by-step explanation:

∠A = ½·132° = 66°

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Over the last 3 months, Janet exercised a total of 101 hours. She exercised 4 hours more during the second month than the first

olganol [36]

In 1st month let she exercised h hours

in second month she exercised h+4 hours

in third month she exercised h+4-3=h+1 hours

Now

h+h+4+h+1=101
3h+5=101
3h=96
h=32hours

3 0

2 years ago

Read 2 more answers

Copy and complet the table compare the values of 2^x-2 with the values of 2^x-2

Vladimir79 [104]

#2^(x-2)

For 2

2^(2-2)=2⁰=1

For 3

2^(3-2)=2

For 4

2^(4-2)=2²=4

For 5

2^{5-2}=2³=8

For 6

2^{6-2}=2⁴=16

#2^x-2

For 2

2²-2=2

For 3

2³-2=6

For 4

2⁴-2=14

For 5

2⁵-2=30

For 6

2⁶-2=62

3 0

2 years ago

Read 2 more answers

Here is an expression.

sp2606 [1]

Answer:

Step-by-step explanation:

is the situation could the expression model.

6 0

2 years ago

UkoKoshka [18]

Answer:

-8n + 9

Step-by-step explanation:

Given that,

A = -3n + 2

B = 5n - 7

Before solving you have to know that,

( + ) × ( + ) = ( + )

( - ) × ( - ) = ( + )

( + ) × ( - ) = ( - )

Let us solve now.

A - B

-3n + 2 -(5n - 7)

-3n + 2 - 5n + 7

Combine like terms

-3n - 5n + 2 + 7

-8n + 9

Hope this helps you.

Let me know if you have any other questions :-)

5 0

2 years ago

1. Slove the system of equations, first by graphing, and then algebraically. (8 points) y=x-2 and y=-2x+7

Anton [14]

The solution of the equation is $x=3$ and $y=1$

Explanation:

The equations are $y=x-2$ and $y=-2 x+7$

First we shall solve the equation graphically.

The image of the graph is attached below.

This contains the solution to the system of equations.

The equations $y=x-2$ and $y=-2 x+7$ are plotted on the graph.

The intersection of these two equations are the solutions of the system of equations.

Thus, the intersection of the two equations are $x=3$ and $y=1$

Now, we shall solve the equation algebraically.

Let us solve the equation using substitution method.

Let us substitute $y=x-2$ in $y=-2 x+7$ , we get,

$x-2=-2x+7$

Adding both sides by 2x, we have,

$3x-2=7$

Adding both sides by 2, we get,

$3x=9$

Dividing both sides by 3,

$x=3$

Thus, the value of x is 3.

Substituting $x=3$ in $y=x-2$ , we get,

$y=3-2\\y=1$

Thus, the value of y is 1.

Hence, The solution of the equation is $x=3$ and $y=1$

4 0

3 years ago