Answer:
AKPOS/ACGF = 28√3 -48 ≈ 0.497423
Step-by-step explanation:
Let's assume the square is a unit square. Then the height of the triangle is ...
1 +(√3)/2 = h
and half the base of the triangle is ...
h/√3 = (√3)/3 +1/2 = b/2
The area of the triangle is the product of these:
A = (1/2)bh
= (2 +√3)/2 × (3 +2√3)/6
= (6 +3√3 +4√3 +6)/12 = (12 +7√3)/12
So, the ratio of the area of the square to that of the triangle is the inverse of this, or ...
(square area)/(triangle area) = 12/(12+7√3)
(square area)/(triangle area) = 28√3 -48
U can see if it is a right triangle bu using the pythagorean theorem (or however it is spelled)
a^2 + b^2 = c^2....where a and b are the legs and c is the hypotenuse (the largest side)
so lets sub our numbers in and see if they equal
33^2 + 56^2 = 65^2
1089 + 3136 = 4225
4225 = 4225.......correct...so YES, this is a right triangle
Answer:
B=9
Step-by-step explanation:
b+4=2b-5
b-2b+4=-5
b-2b=-5-4
-b=-5-4
-b=-9
b=9
Y = mx + b, where m = slope = rise/run and b, the y intercept value
m = 1/1 = 1, then y = x + b.
We notice that y intercept is = - 1
And the equation is:
y = x - 1
