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3 years ago

Find the equation of the line that is parallel to the

Mathematics

1 answer:

zepelin [54]3 years ago

6 0

9514 1404 393

Answer:

y = -x -12

Step-by-step explanation:

The slope of the line you want is the same as the slope of the line you have: -1. Then the point-slope equation of the line is ...

y -k = m(x -h) . . . . . . line of slope m through point (h, k)

y -(-7) = -1(x -(-5))

y = -x -5 -7 . . . . subtract 7, eliminate parentheses

y = -x -12 . . . slope-intercept equation

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Does anyone know this one?

mel-nik [20]

Answer:

-3

Step-by-step explanation:

(-5) - (-2) = (-3)

hope it helps

6 0

2 years ago

Read 2 more answers

Every hour of driving uses

xenn [34]

Answer:

45 gallons

Step-by-step explanation:

1 hour = 3 gallons

2 hours = 6 gallons

3 hours = 9 gallons

4 hours = 12 gallons

5 hours = 15 gallons

10 hours = 30 gallons

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4 0

3 years ago

10 points!! Pls help with 5 and 6

marissa [1.9K]

Answer:

I only know number 5 so here it is

the solution for the left is: 2x6=12

the solution for the right is: 5x3+4x1=15+4=19

and the answers are: 1.12 . 2.19

5 0

2 years ago

Caden states that n^2 +3n + 2n is an equivalent expression to 6n. Why is Caden's statement incorrect?

malfutka [58]

$\begin{gathered} \text{The simplification of n}^2+3n+2n\text{ is:} \\ i)n^2+5n \\ By\text{ collecting common term, this can be written in form of:} \\ ii)\text{ n(n+5)} \end{gathered}$

Thus, options A and D hold, from the simplifications above.

Let's consider the validity of the remaining options provided.

$\begin{gathered} \text{For option B)} \\ \text{substitute for n=1 into the expression n}^2+3n+2n,\text{ we have} \\ 1^2+3(1)+2(1)=1+3+2=6 \\ \text{substitute for n=1 into the expression 6n, we have} \\ 6(1)=6 \\ \text{Thus, the expression n}^2+3n+2n\text{ is equivalent to 6n, for n=1} \end{gathered}$ $\begin{gathered} \text{For option C)} \\ \text{The expression n}^2+3n+2n\text{ does not simplify to 7n} \end{gathered}$ $\begin{gathered} \text{For option E)} \\ \text{substitute for n=4 into the expression n}^2+3n+2n,\text{ we have:} \\ 4^2+3(4)+2(4)=16+12+8=36 \\ \text{substitute for n=6 into the expression 6n, we have:} \\ 6(4)=24 \\ \text{Thus, the two(2) expressions are not equivalent to each other, for n=4} \end{gathered}$ $\begin{gathered} \text{For option F)} \\ \text{substitute for n=3 into the expression n}^2+3n+2n,\text{ we have:} \\ 3^2+3(3)+2(3)=9+9+6=24 \\ \text{substitute for n=3 into the expression 6n, we have:} \\ 6(3)=18 \\ \text{Thus, the two(2) expressions are not equivalent to each other, for n=3} \end{gathered}$

Hence, the correct options that apply are options A, D, E and F

7 0

11 months ago

JK is formed by J(-12,3) and K(8,-5). If line r is the perpendicular bisector of JK, write an equation for r in slope-intercept

dem82 [27]

Answer:

y = 5/2x + 4

Step-by-step explanation:

Midpoint of JK:

x = (-12 + 8)/2 = -4/2 = -2
y = (3 - 5)/2 = -2/2 = -1

Slope of the line JK:

m = (-5 - 3)/(8 - (-12)) = -8/20 = -2/5

Perpendicular lines have negative reciprocal slopes.

So the line r has a slope 5/2 and passes through the point (-2, -1)

Equation of r:

y = 5/2x + b
-1 = 5/2(-2) + b
-1 = -5 + b
b = 5 - 1
b = 4

So the equation is:

y = 5/2x + 4

3 0

3 years ago