X = 25
a^2 + b^2 = c^2
19^2 +16^ = c^2
617 = c^2
(Square root 617)
x=24.83
x=25
Answer:
FG=30
Step-by-step explanation:
Since we know that Point G is on the Segment FH, it doesn't really matter where G is, but we can know for certain that:

We are given that FH is 4x, GH is x, and FG is 2x+10. Substitute:

Solve for x. On the right, combine like terms:

Subtract 3x from both sides:

So, the value of x is 10.
To find the value of FG, substitute 10 into its x:

Multiply:

Add:

And we're done!
Hi there!

The two trapezoids are similar, so we can determine a common scale factor:
OL/UR = NM/TS
9/3 = 6/2
3 = 3
Trapezoid ONML is 3x larger than UTSR, so:
RS = 4, LM = y
3RS = LM
3 · 4 = y = 12.
Find x using the same method:
3UT = ON
3(2x+1) = 4x + 9
6x + 3 = 4x + 9
2x = 6
x = 3.
<span>this is the answer = "center center" I hope this help.. </span>
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