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kaheart [24]
3 years ago
6

Write the equation of the line that passes through (-4,3) and is parallel to y = -2x - 8.

Mathematics
1 answer:
kobusy [5.1K]3 years ago
8 0

Answer:

y = -2x - 5

Step-by-step explanation:

Let the equation if the line be y = mx + c

since the line is parallel to y = -2x - 8, their gradients/slope must be the same (aka m = -2)

sub (-4, 3):

3 = -2(-4) + c

c = -5

therefore, the equation of the line is y = -2x - 5

This is a question on coordinate geometry. If you wish to venture further into it/understand this topic better, you may want to follow my Instagram account (learntionary), where I post some of my own notes on certain topics and also some tips that may be useful to you :)

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Find the Y-coordinate of point P that lies 1/3 along segment RS, where R (-7, -2) and S (2, 4).
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Solution:

Given that the point P lies 1/3 along the segment RS as shown below:

To find the y coordinate of the point P, since the point P lies on 1/3 along the segment RS, we have

\begin{gathered} RP:PS \\ \Rightarrow\frac{1}{3}:\frac{2}{3} \\ thus,\text{ we have} \\ 1:2 \end{gathered}

Using the section formula expressed as

[\frac{mx_2+nx_1}{m+n},\frac{my_2+ny_1}{m+n}]

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Thus, by substitution, we have

\begin{gathered} [\frac{1(2)+2(-7)}{1+2},\frac{1(4)+2(-2)}{1+2}] \\ \Rightarrow[\frac{2-14}{3},\frac{4-4}{3}] \\ =[-4,\text{ 0\rbrack} \end{gathered}

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0

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1 year ago
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-8 + 6.45z - 3.25z

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