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3 years ago

Find the mean of the picture below?

Mathematics

1 answer:

Kobotan [32]3 years ago

8 0

The believe mean is four

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A painter is using a 8-foot ladder to paint a house. The painter places the ladder 4 feet from the house. How high up the wall d

zavuch27 [327]

Answer:

32 feet high

Step-by-step explanation:

7 0

2 years ago

Solve for j: j + j / 2 + J + 5 = 45

Georgia [21]

Answer:

j:5j/2+5=45 Or j=16 how you put it was a little confusing

5 0

1 year ago

How many solutions does the equation −4y + 4y + 2 = 2 have?

antiseptic1488 [7]

Answer:

Step-by-step explanation:

Let's solve your equation step-by-step.

−4y+4y+2=2

Step 1: Simplify both sides of the equation.

−4y+4y+2=2

(−4y+4y)+(2)=2(Combine Like Terms)

2=2

Step 2: Subtract 2 from both sides.

2−2=2−2

0=0

Answer:

All real numbers are solutions.

8 0

2 years ago

Equivalent fraction of 3/12

Lady bird [3.3K]

1/4 is the answer.....,,

7 0

3 years ago

Two airplanes are flying in the air at the same height. Airplane A is flying east at 300mi/h and airplane B is flying north at 2

Ipatiy [6.2K]

Answer:

$\frac{dAB}{dt}=340 mil/h$

Step-by-step explanation:

The change of distance over time of the plain A is 300 mi/hour and 200 mi/hour for plane B. O is the point of the airport.

So, the distance from A to O AO = 90 miles and BO = 120 miles.

Now, we have a right triangle here. We can use the Pythagorean theorem, so the distance between the planes will be:

$AB^{2} =AO^{2}+BO^{2}$ (1)

$AB =\sqrt{AO^{2}+BO^{2}}=$

$AB =\sqrt{90^{2}+120^{2}}=150 miles$

If we take the derivative of the equation (1) we could find the change of the distance between planes.

$2AB\frac{dAB}{dt}=2AO\frac{dAO}{dt}+2BO\frac{dBO}{dt}$

$2*150\frac{dAB}{dt}=2*90*300+2*120*200=102000 mil/h$

$\frac{dAB}{dt}=\frac{102000}{150*2}$

Finally,

$\frac{dAB}{dt}=340 mil/h$

I hope it helps you!

6 0

2 years ago