For there to be 1 car, we consider two possible outcomes:
The first door opened has a car or the second door opened has a car.
P(1 car) = 2/6 x 4/5 + 4/6 x 2/5
P(1 car) = 8/15
For there to be no car in either door
P(no car) = 4/6 x 3/5
P(no car) = 2/5
Probability of at least one car is the sum of the probability of one car and probability of two cars:
P(2 cars) = 2/6 x 1/5
= 1/15
P(1 car) + P(2 cars) = 8/15 + 1/15
= 3/5
Answer:
Solution is invalid
Step-by-step explanation:
Let the time when they will have the same water content be x hours
At x hours;
For the first tank, the content will be;
50 + 10x
For the second;
29 + 3x
Equating both, will give us x
29 + 3x = 50 + 10x
We will get x as a negative number here
Since number of hours can not be negative, the solution is invalid
Times it by 3 and see what u get try see if it work
