Answer:
There are no vertical asympotes for this rational function.
Step-by-step explanation:
For rational functions, a vertical asymptote exists for every value of the independent variable such that function become undefined, that is, such that denominator is zero. Let be the following rational function:
, ![0\le p < 100](https://tex.z-dn.net/?f=0%5Cle%20p%20%3C%20100)
There is a vertical asymptote for this case:
![100-p = 0](https://tex.z-dn.net/?f=100-p%20%3D%200)
![p = 100](https://tex.z-dn.net/?f=p%20%3D%20100)
Which is out of the interval given to the rational function. Hence, we conclude that there are no vertical asympotes for this rational function.
Answer:
Perimeter = 18.7 units
Area = 13.5 units²
Step-by-step explanation:
Perimeter of ADEC = AD + DE + EC + AC
Length of AD = 3 units
By applying Pythagoras theorem in ΔDBE,
DE² = DB² + BE²
DE² = 3² + 3²
DE = √18
DE = 4.24 units
Length of EC = 3 units
By applying Pythagoras theorem in ΔABC,
AC² = AB² + BC²
AC² = 6² + 6²
AC = √72
AC = 8.49 units
Perimeter of ADEC = 3 + 4.24 + 3 + 8.49
= 18.73 units
≈ 18.7 units
Area of ADEC = Area of ΔABC - Area of ΔBDE
Area of ΔABC = ![\frac{1}{2}(AB)(BC)](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%28AB%29%28BC%29)
= ![\frac{1}{2}(6)(6)](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%286%29%286%29)
= 18 units²
Area of ΔBDE = ![\frac{1}{2}(BD)(BE)](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%28BD%29%28BE%29)
= ![\frac{1}{2}(3)(3)](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%283%29%283%29)
= 4.5 units²
Area of ADEC = 18 - 4.5
= 13.5 units²
Neither p or z ISNT A NUMBER SO DO ONE WITH A NUMBER THAT QUESTIPON IS WRONG
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Answer:
They are congruent by SAS
Step-by-step explanation:
MQ=PN
The angles with markings also go together
The line right in the middle is the second side because of the reflexive property
Answer:
The slope is 5/-2.
Step-by-step explanation:
Slope is y1-y2 over m1-m2 (rise over run). The first ordered pair is -2 (m1) and 11 (y1). We then subtract the second ordered pair (4 (m2) and -4 (y2)) from the first.
11 - (-4) = 11 + 4 = 15
-2 - 4 = -6
Remember, slope is rise over run (y over x), so the slope is 15/-6. Now, we must simplify. 15/-6 = 5/-2
Dean went wrong because he thought that slope was run over rise (x over y). If he had switched the two numbers, his answer would have been correct.