Answer:
Consultant B :)
Step-by-step explanation:
Solution:
The given Polynomial is :

By Rational Root theorem the of Zeroes of the Polynopmial are:

But , 
So, no root of this polynomial is real.
Therefore, All the four roots of Polynomial are imaginary.
So, we can't say whether the number k=2, is an upper or lower bound of the polynomial
.
Hi there! The answer is B. it would be less steep.
The change of the function (in this case) influences the slope of the line. Since we've modified the slope from 5 to 3 / 4, the line will be less steep.
Answer:
sorry type it out
Step-by-step explanation:
Answer:
The variable, y is 11°
Step-by-step explanation:
The given parameters are;
in triangle ΔABC;
in triangle ΔFGH;
Segment
= 14
Segment
= 14
Segment
= 27
Segment
= 19
Segment
= 19
Segment
= 2·y + 5
∡A = 32°
∡G = 32°
∡A = ∠BAC which is the angle formed by segments
= 14 and
= 19
Therefore, segment
= 27, is the segment opposite to ∡A = 32°
Similarly, ∡G = ∠FGH which is the angle formed by segments
= 14 and
= 19
Therefore, segment
= 2·y + 5, is the segment opposite to ∡A = 32° and triangle ΔABC ≅ ΔFGH by Side-Angle-Side congruency rule which gives;
≅
by Congruent Parts of Congruent Triangles are Congruent (CPCTC)
∴
=
= 27° y definition of congruency
= 2·y + 5 = 27° by transitive property
∴ 2·y + 5 = 27°
2·y = 27° - 5° = 22°
y = 22°/2 = 11°
The variable, y = 11°