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dalvyx [7]
3 years ago
11

Without solving, NO SOLUTION describes which equation?

Mathematics
2 answers:
svetlana [45]3 years ago
8 0

Answer:

1: y=y+1

2: 6a = 9a

Step-by-step explanation:

Without solving, NO SOLUTION describes which equation?

Answer: y=y+1

For which equation is zero a reasonable solution?

Answer: 6a = 9a

CaHeK987 [17]3 years ago
5 0

Answer:

The equation 'y = y + 1' represents NO SOLUTION.

Hence, option 'C' is true.

Step-by-step explanation:

a)

6a = 9a

subtract 9a from both sides

6a - 9a = 9a - 9a

-3a = 0

divide both sides by -3

-3a / -3 = 0/-3

Simplify

a = 0

b)

5x = 28

divide both sides by 5

5x/5 = 28/5

x = 28/5

c)

y = y + 1

subtract y from both sides

y - y = y+1-y

0 = 1

These sides are not equal, so

NO SOLUTION!

d)

y + 5 = 12

subtract 5 from both sides

y + 5 - 5 = 12 - 5

y = 7

Conclusion:

Therefore, the equation 'y = y + 1' represents NO SOLUTION.

Hence, option 'C' is true.

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Solution:

The given Polynomial is :

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\pm\frac{1}{5},\pm\frac{2}{5},\pm\frac{4}{5},\pm1,\pm2,\pm4

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So, no root of this polynomial is real.

Therefore, All the four roots of Polynomial are imaginary.

So, we can't say whether the number k=2, is an upper or lower bound of the polynomial f(x) = 5x^4 + 4x^3 - 2x^2 + 2x + 4=5( x^4 + \frac{4}{5}x^3 - \frac{2}{5}x^2 + \frac{2}{5}x + \frac{4}{5}).

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Find the value of the variable.
nalin [4]

Answer:

The variable, y is 11°

Step-by-step explanation:

The given parameters are;

in triangle ΔABC;          {}              in triangle ΔFGH;

Segment \overline {AB} = 14         {}               Segment \overline {FG} = 14

Segment \overline {BC} = 27         {}              Segment \overline {GH} = 19

Segment \overline {AC} = 19         {}               Segment \overline {FH} = 2·y + 5

∡A = 32°                       {}                ∡G = 32°

∡A = ∠BAC which is the angle formed by segments \overline {AB} = 14 and \overline {AC} = 19

Therefore, segment \overline {BC} = 27, is the segment opposite to ∡A = 32°

Similarly, ∡G = ∠FGH which is the angle formed by segments \overline {FG} = 14 and \overline {GH} = 19

Therefore, segment \overline {FH} = 2·y + 5, is the segment opposite to ∡A = 32° and triangle ΔABC ≅ ΔFGH by Side-Angle-Side congruency rule which gives;

\overline {FH} ≅ \overline {BC} by Congruent Parts of Congruent Triangles are Congruent (CPCTC)

∴ \overline {FH} = \overline {BC} = 27° y definition of congruency

\overline {FH} = 2·y + 5 = 27° by transitive property

∴ 2·y + 5 = 27°

2·y = 27° - 5° = 22°

y = 22°/2 = 11°

The variable, y = 11°

8 0
2 years ago
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