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PtichkaEL [24]
3 years ago
10

Form a quadrilateral with exactly one pair of parallel sides.

Mathematics
1 answer:
Julli [10]3 years ago
6 0

Answer:

A trapezoid is a quadrilateral with exactly one pair of parallel sides.

Step-by-step explanation:

hope this helped

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How many solutions exist for the given equation?<br>12×+1=3(4×+1)-2​
Ipatiy [6.2K]

Answer:

infinite Solutions

Step-by-step explanation:

12x+1 = 12x+3-2

12+1 = 12x+1

The equation is same on both sides, so x can be anything.

5 0
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Can someone pl help. Thx
kakasveta [241]

Answer:

3.10?

Step-by-step explanation:

i dont know sorry if its wrong

7 0
3 years ago
If seven-eights of a pound of meatloaf was shared equally among the 3 people, what fraction of a pound did each person receive
Lubov Fominskaja [6]

Answer:

7/24

Step-by-step explanation:

7/8 of a pound of meatloaf is divided by 3 people so each person will receive (7/8)/3 = 7/24 of a pound of meatloaf

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2 years ago
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Hello, happy Friday, I am just here with some geometry questions.
Virty [35]

Answer:

<u>Given triangle:</u>

  • ΔXYZ
  • X(-1,2), Y(2,1), Z(-1, -2)

<u>D₀.₅(ΔXYZ) results in:</u>

  • (x, y) → (0.5x, 0.5y)
  • X'(-0.5, 1), Y'(1, 0.5), Z(-0.5, -1)

5 0
3 years ago
8. The base of a circular cone has a diameter of 10 cm and an altitude of 10 cm. The cone is filled with water. A sphere is lowe
nataly862011 [7]

Answer:

The volume of water that remains on the cone is 523.6 cm³

Step-by-step explanation:

To solve this problem you have to keep in mind the formules that describes the volume of a cone and the volume of a sphere.

Volume of a cone = (πr²h)/3

Volume of a sphere = (4/3)πr³

So, if the base of the cone has a diameter of 10 cm, its radius is 5 cm. Its altitude is 10 cm. ⇒Volume = (πr²h)/3 ⇒ Volume = [π(5²)10) ⇒

          Volume = 785.4 cm³. This is the initial volume of water.

Now if the sphere fits in the cone and half of it remains out of the water, the other half is inside the cone. Estimating the volume of the sphere and dividing it by two, you find the volume of water that was displaced.

Volume of a sphere = (4/3)πr³, here the radius is the same of the base of the cone (5 cm).

⇒ Volume = (4/3)π(5³)  ⇒ Volume = 523.6 cm³ ⇒ The half of this volume is 261.8 cm³. This is the volume of water displaced.

⇒ The volume of water that remains on the cone is 523.6 cm³ (785.4 cm³- 261.8 cm³)

6 0
3 years ago
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