Answer:
you cant round that to 30
Step-by-step explanation
29.20
29.2 2 is less than 5
so you cant round you can only round if the .tens place is 5 or more
0x1=0
1x2=2
2x3=6
3x4=12
4x5=20
Answer:
c. none of the above
Step-by-step explanation:
(-6+3)= -3
2--3=2+3=5
5+4c cant add them since they arent like terms
final answer 5+4c and that option isnt here
Answer:
-0.3*0.2*12, multiply -0.3 by 0.2 to get -0.06, now multiply 12 by it to get, -0.72.
Step-by-step explanation:
Answer:
probability that the other side is colored black if the upper side of the chosen card is colored red = 1/3
Step-by-step explanation:
First of all;
Let B1 be the event that the card with two red sides is selected
Let B2 be the event that the
card with two black sides is selected
Let B3 be the event that the card with one red side and one black side is
selected
Let A be the event that the upper side of the selected card (when put down on the ground)
is red.
Now, from the question;
P(B3) = ⅓
P(A|B3) = ½
P(B1) = ⅓
P(A|B1) = 1
P(B2) = ⅓
P(A|B2)) = 0
(P(B3) = ⅓
P(A|B3) = ½
Now, we want to find the probability that the other side is colored black if the upper side of the chosen card is colored red. This probability is; P(B3|A). Thus, from the Bayes’ formula, it follows that;
P(B3|A) = [P(B3)•P(A|B3)]/[(P(B1)•P(A|B1)) + (P(B2)•P(A|B2)) + (P(B3)•P(A|B3))]
Thus;
P(B3|A) = [⅓×½]/[(⅓×1) + (⅓•0) + (⅓×½)]
P(B3|A) = (1/6)/(⅓ + 0 + 1/6)
P(B3|A) = (1/6)/(1/2)
P(B3|A) = 1/3
