All categories

3 years ago

MULTIPLE CHOICE QUESTION PLEASE HELP

Mathematics

1 answer:

Sonja [21]3 years ago

7 0

Answer: A

Step-by-step explanation:

You might be interested in

The sum of partial products is equal to the final product?

Shkiper50 [21]

The sum of partial product is not always equal to a final product

8 0

3 years ago

Alvin is 9 years older than Elga. The sum of their ages is 89. What is Elga's age?

Mekhanik [1.2K]

Answer:

Alvin: 49

Elga: 40

Step-by-step explanation:

The equation is 89 = x + (x-9).
Remove the parenthesis and combine the like terms. 89 = 2x - 9
Add 9 on both sides. 98 = 2x
Divide by 2 on both sides. x = 49
49 is the age of Alvin. (49-9) 40 is the age of Elga.

7 0

3 years ago

Read 2 more answers

What is the unit cost per bottle if a pack of 6 bottles of juice sells for $4.80

juin [17]

Answer: i think 0.8.

Step-by-step explanation:

7 0

2 years ago

The relationship between 4s in 44,000

Ganezh [65]

The 4 on the left side is 10x more than the 4 on the right. This only works if the numbers are next to each other and are the same.

5 0

3 years ago

Write the partial fraction decomposition fro the ration expression below

zlopas [31]

$\dfrac{5x-2}{(x-1)^2}=\dfrac a{x-1}+\dfrac b{(x-1)^2}$
$5x-2=a(x-1)+b$

Since $5x-2=5x-5+3=5(x-1)+3$ , it follows that $a=5$ and $b=3$ , so

$\dfrac{5x-2}{(x-1)^2}=\dfrac5{x-1}+\dfrac3{(x-1)^2}$

$\dfrac{x^3+x^2+x+2}{x^4+x^2}=\dfrac{x^3+x+x+2}{x^2(x^2+1)}=\dfrac ax+\dfrac b{x^2}+\dfrac{cx+d}{x^2+1}$
$x^3+x^2+x+2=ax(x^2+1)+b(x^2+1)+(cx+d)x^2$
$x^3+x^2+x+2=(a+c)x^3+(b+d)x^2+ax+b$

When $x=0$ , you find that $b=2$ . It's also clear that $a=1$ . So the remaining constants must be $1+c=1\implies c=0$ and $2+d=1\implies d=-1$ , and so you get

$\dfrac{x^3+x^2+x+2}{x^4+x^2}=\dfrac1x+\dfrac2{x^2}-\dfrac1{x^2+1}$

6 0

3 years ago