the area of the first shape is 4 times 12 which is 48 and the area of the second shape is 2 times 10 which is 20
48+20= 68 mi2
10≤n<100
So the number of two digit numbers is 99-10+1=90
The only combinations that sum to 5 are 14, 23, 32, 41, 50 so
P(sum=5)=5/90
P(sum=5)=1/18
Maybe 4.80
Step-by-step explanation:
Answer:
Step-by-step explanation:
By the trapezoid midsegment theorem,
2x = (x-6) + (2x-8)
2x = x - 6 + 2x - 8
2x = 3x - 14
x = 14
So we know AD = 8, EF = 14, and BC = 20
