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3 years ago

I dont understand any of this please help :(

Mathematics

2 answers:

podryga [215]3 years ago

8 0

Answer:1, 63, and 25

Step-by-step explanation:

Ludmilka [50]3 years ago

8 0

Answer:

first one is 1/2

the next one is 1/2

the last one is 1/4

Step-by-step explanation:

i just did it

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50 POINTS AND BRAINLIST

Umnica [9.8K]

Answer:

$\sf x = 61.9^{\circ \:}$

given:

opposite side = 15

hypotenuse side = 17

using sine rule:

$\sf sin(x) = \dfrac{opposite}{hypotenuse}$

$\sf sin(x) = \dfrac{15}{17}$

$\sf x = sin^{-1}(\dfrac{15}{17} )$

$\sf x = 61.9^{\circ \:}$

6 0

3 years ago

Read 2 more answers

£980 is divided between Caroline, Sarah & Gavyn so that Caroline gets twice as much as Sarah, and Sarah gets three times as

Nitella [24]

Sarah has received £ 294

Solution:

Given that £980 is divided between Caroline, Sarah & Gavyn

Let "c" be the amount received by caroline

Let "s" be the amount received by sarah

Let "g" be the amount received by gavyn

Caroline gets twice as much as Sarah

amount received by caroline = twice as much as Sarah

amount received by caroline = 2(amount received by sarah)

c = 2s ---- eqn 1

Sarah gets three times as much as Gavyn

amount received by sarah = three times as much as Gavyn

amount received by sarah = 3(amount received by gavyn)

s = 3g ------- eqn 2

Given that total amount is 980

c + s + g = 980 --- eqn 3

Let us solve eqn 1, 2, 3 to get values of "c" "s" "g"

From eqn 2,

$g = \frac{s}{3}$ --- eqn 4

Substitute eqn 1 and eqn 4 in eqn 3

$2s + s + \frac{s}{3} = 980\\\\\frac{6s + 3s + s}{3} = 980\\\\6s + 3s + s = 980 \times 3\\\\10s = 2940\\\\s = 294$

Thus sarah has received £ 294

7 0

3 years ago

Suppose y varies directly as x. if y = 3 when x = 15, find when y = 5.

julia-pushkina [17]

Answer:

X = -9

Step-by-step explanation:

y = k X for some fixed number constant k.

-5 = k (15)

k = -5/15 = -1/3

So y = (-1/3)X

When y = 3 ---> 3 = (-1/3)X

X = -9

4 0

3 years ago

Two students used different methods to evaluate 4 1/2 divided by 3/4

o-na [289]

Answer:

Step-by-step explanation:

4 0

4 years ago

Nikita ran a 5-kilometer race in 39 minutes (0.65 of an hour) without training beforehand. In the first part of the race, her av

algol [13]

First part of the race

speed1, s1 = 8.75 km/h
distance1 = 5 km - x
time 1 = 0.65 h - t

Second part of the race

speed2, s2 = 6 km/h
distance2 = x
time2 = t

s2 = x/t = 6 ⇒ t = x / 6

s1 = [5 - x] / [0.65 - t] = 8.75

5 - x = 8.75 [0.65 - t]

5 -x = 8.75(0.65) - 8.75t

5 - x = 5.6875 - 8.75 (x/6)

5 - x = 5.6875 - 1.4583x

1.4583 x - x = 5.6875 - 5

0.4583 x = 0.6875

x = 0.6875 / 0.4583 = 1.5

6 0

3 years ago