Answer: 3
Step-by-step explanation:
A simple way to calculate the distance between numbers on a number line is to count every number between them. A faster way is to find the distance by taking the absolute value of the difference of those numbers. We have to find PQ. TAking the difference we have 94-91= 3.
1) You'll have to get raid of the fraction by multiplying 10ac by 11, x/11 by 11 which the 11's cancels out and -3 multiplied by 11 .
2)Now you have 10ac -x = -33. Add x on both sides of the equal sign you get 10ac = -33 + x
3) Divide both sides by 10c to get "a" by itself, so "a" = -33+x divided by 10c
That is true, I don,t quite know how to explain it but I just did this problem yesterday.
Answer: D
Step-by-step explanation:
Standard Deviation σ2 =
Σ(xi - μ)2/N
=(1 - 5.3)2 + ... + (9 - 5.3)2/10
=68.1/10
= 6.81
σ = √6.81
= 2.60959767014
B) σ2 =
Σ(xi - μ)2/N
=(3 - 61.7)2 + ... + (99 - 61.7)2/10
=58414.1/10
= 5841.41
σ = √5841.41
= 76.429117488036
C) (1 - 11.4)2 + ... + (1 - 11.4)2/10
=8758.4/10
= 875.84
σ = √875.84
= 29.59459410095
D) (79 - 79)2 + ... + (79 - 79)2/10
=0/10
= 0
σ = √0
= 0
I hope this helps, mark as Brainliest please.
