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alexandr402 [8]

3 years ago

15

Basic triangle proofs please help

2 answers:

max2010maxim [7]3 years ago

8 0

BD is congruent to BD by the reflexive property
AD is congruent to DC because they are both created by the midpoint D
so with all the together you can say the triangle are similar by SSS

seropon [69]3 years ago

4 0

Answer:

Step-by-step explanation:

Hope this helps u !!!

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Can the formulas A = lw or A = bh be used to find the area of a square? Why or why not? pls answer !!!!!!

andrey2020 [161]

A=lw and A=bh are the same equation in terms of a square you just need to simply think of the swuare as standing up with bh and lw as laying down
they both work

7 0

3 years ago

5+ 3 cos ½x = 7<br>how to find the x?

Anon25 [30]

Answer:

$x=\pm 2 arcos(\frac{2}{3})+4k\pi$

where $k$ is an integer

Step-by-step explanation:

$5+3\cos(\frac{1}{2}x)=7$

We are going to isolate the trig expression first.

Subtract 5 on both sides:

$3\cos(\frac{1}{2}x)=2$

Divide both sides by 3:

$\cos(\frac{1}{2}x)=\frac{2}{3}$

Now since $\cos(u)$ is even then $\cos(u)=\cos(-u)$ .

So we have:

$\cos(\frac{1}{2}x)=\frac{2}{3}$

implies:

$\frac{1}{2}x=arccos(\frac{2}{3})+2k\pi$

Multiply both sides by 2:

$x=2arccos(\frac{2}{3})+4k\pi$

or

$-\frac{1}{2}x=arcos(\frac{2}{3})+2k\pi$

Multiply both sides by -2:

$x=-2arccos(\frac{2}{3})-4k\pi$

So we can say the solution is:

$x=\pm 2arcos(\frac{2}{3})+4k\pi$

( $k$ is an integer)

5 0

3 years ago

Divide the following polynomial.<br><br> (x^2 - 4) (x - 1)

vovikov84 [41]

(x2 + x + 2) • (x - 2)

—————————

x - 1

4 0

3 years ago

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How can I solve this:

Fynjy0 [20]

Hey !

The Sum of Roots is -6

Manipulate the Equation to Get :

$(3a + 6) {x}^{2} + (2a - 4)x + (a + 4) = 0$

Now, by Viete,

$- 6 = \frac{(4 - 2a)}{(3a + 6)}$

$18a + 36 = 2a - 4$

$16a = - 40$

$= > a = \frac{ - 5}{2} = - 2.5$

4 0

4 years ago

7x 2/12 as a mixed number

iren2701 [21]

7/6 would be the correct answer, I believe.

7 0

3 years ago

Read 2 more answers