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4 years ago

Please help!! And pls show work

Mathematics

1 answer:

coldgirl [10]4 years ago

8 0

<h3>The answer to your question is k (-3) = 21!</h3>

Here's how I got this answer:

K(a) = 2a^2 - a

K(a) = 2a^2 - a K(-3) = 2(-3)^2 - (-3)

K(a) = 2a^2 - a K(-3) = 2(-3)^2 - (-3)K(-3) = 2(9) + 3

K(a) = 2a^2 - a K(-3) = 2(-3)^2 - (-3)K(-3) = 2(9) + 3K (-3) = 18 + 3

K(a) = 2a^2 - a K(-3) = 2(-3)^2 - (-3)K(-3) = 2(9) + 3K (-3) = 18 + 3K (-3) = 21

I hope this helps!

Also sorry for the late answer, I just got the notification that you replied to my comment, I hope I came in time!

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The base of a triangle is 3m and its height is $10 \frac{1}{2}$ m.

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Solution:

Given, base = 3m, height = $10 \frac{1}{2}$ m
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Answer:

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Hope you could understand.

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Read 2 more answers

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$\\(i)\\
\text{We know that the average rate of change of a function f(x) on inerval [a,b] is}\\
\\
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\text{so using this the average rate of chang of g for x on interval }[3,7] \text{ is}\\
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$\\(ii)\\ \text{Average rate of chang of f for x on interval }[3,7] \text{ is}\\
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$\\(iii)\\
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$\\(iv)\\
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\text{since the value of g is 2 at x=5. so }\\
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