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1 answer:
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<em>Note: Since you missed to add the figure. So, after a little research I am kind of able to find the figure and hence, assuming it as a reference. Hence, I am attaching the figure and solution of that figure is also visible in the same figure.</em> Please check the attached figure (a)
Answer:
Segment B'D' will be parallel to segment BD and will be shorter than segment BD. Please see the attached figure (a) for better understanding.
Step-by-step explanation:
As we know that there are certain rules when a quadrilateral is dilated by a certain scale centered around a certain point.
So,
Let suppose P(a, b) is the point.
The dilation rule by a scale factor of 1 over 3 or (1/3) centered around (1, 2) is
P(a, b) →
Hence,
A(1, 2) → A'(1, 2)
B(2, 3) → B'(4/3, 7/3)
C(4, 2) → C'(2, 2)
D(2, 1) → D'(4/3, 5/3)
The attached figure show that if we draw the all these points in the coordinate plan i.e. A(1, 2), B(2, 3), C(4, 2), D(2, 1) and A'(1, 2), B'(4/3, 7/3), C'(2, 2), D'(4/3, 5/3), we can determine that Segment B'D' will be parallel to segment BD and will be shorter than segment BD.
<em>Keywords: dilation, quadrilateral, segment</em>
<em> Learn more about dilation from brainly.com/question/7569824</em>
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Answer:
a) SPAZ is equilateral.
b) Diagonals SA and PZ are perpendicular to each other.
c) Diagonals SA and PZ bisect each other.
Step-by-step explanation:
At first we form the triangle with the help of a graphing tool and whose result is attached below. It seems to be a paralellogram.
a) If figure is equilateral, then SP = PA = AZ = ZS:
Therefore, SPAZ is equilateral.
b) We use the slope formula to determine the inclination of diagonals SA and PZ:
Since , diagonals SA and PZ are perpendicular to each other.
c) The diagonals bisect each other if and only if both have the same midpoint. Now we proceed to determine the midpoints of each diagonal:
Then, the diagonals SA and PZ bisect each other.
