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gavmur [86]
2 years ago
6

What will be the multipicative inverse of 2/3?

Mathematics
2 answers:
Eddi Din [679]2 years ago
8 0

Answer:

3/2

Step-by-step explanation:

The multiplicative inverse also known as reciprocal implies it is something that is the opposite.

The given value is 2/3, so the opposite would just mean you flip the numerator and denominator. Thus, the reciprocal of 2/3 is 3/2.

poizon [28]2 years ago
6 0

Answer:

3/2

Step-by-step explanation:

The multiplicative inverse is also known as a reciprocal.

The reciprocal of 2/3 is 3/2.

1 ÷ 2/3 = 1 × 3/2

Reciprocals are always used when you divide by a fraction.

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Consider the function f(x)= x² - 4
Arisa [49]

Answer:

(X+2) (X-2) . This is the final answer

Step-by-step explanation:

Solving f(x) = x^2 - 4

A^2 - B^2 is a special case where the original equation before it was foiled is

(A + B) (A - B) because the middle terms will cancel out when foiled.

This means that the equation can be written as

(X + 2)(X - 2) = 0

Each of these you will then set equal to 0 and then solve

X + 2 = 0, X - 2 = 0

X = -2, 2

I hope this helps you! let me now if its right ok <3 :)

4 0
3 years ago
Determine the domain and range of each function<br><br> f(x)=-|x|-2
Alinara [238K]
Find the domain by finding where the function is defined. The range is the set of values that correspond with the domain.

Domain: (- infinity, infinity)
Range: (- infinity, -2)
4 0
3 years ago
BRAINLIESTT ASAP! PLEASE HELP ME :)
Makovka662 [10]

Answer:

2

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
4x−4y=-2 and −9x−4y ​ =-3 solve by adding please !!!
jeyben [28]
1. Add 4x back into -2, you now have -4y=-4x-2. Add +4 from y and now you are at y=-4x+2 and this is the answer!

2. Add -9x back into -3, you now have -4y=9x-3. Add +4 from y and now you are at y=9x-7 and this is your answer!!

I hope this helped! Brainliest? :) -Raven❤️
7 0
3 years ago
United Airlines' flights from Denver to Seattle are on time 50 % of the time. Suppose 9 flights are randomly selected, and the n
Ivanshal [37]

Answer:

<u><em>a) The probability that exactly 4 flights are on time is equal to 0.0313</em></u>

<u><em></em></u>

<u><em>b) The probability that at most 3 flights are on time is equal to 0.0293</em></u>

<u><em></em></u>

<u><em>c) The probability that at least 8 flights are on time is equal to 0.00586</em></u>

Step-by-step explanation:

The question posted is incomplete. This is the complete question:

<em>United Airlines' flights from Denver to Seattle are on time 50 % of the time. Suppose 9 flights are randomly selected, and the number on-time flights is recorded. Round answers to 3 significant figures. </em>

<em>a) The probability that exactly 4 flights are on time is = </em>

<em>b) The probability that at most 3 flights are on time is = </em>

<em>c)The probability that at least 8 flights are on time is =</em>

<h2>Solution to the problem</h2>

<u><em>a) Probability that exactly 4 flights are on time</em></u>

Since there are two possible outcomes, being on time or not being on time, whose probabilities do not change, this is a binomial experiment.

The probability of success (being on time) is p = 0.5.

The probability of fail (note being on time) is q = 1 -p = 1 - 0.5 = 0.5.

You need to find the probability of exactly 4 success on 9 trials: X = 4, n = 9.

The general equation to find the probability of x success in n trials is:

           P(X=x)=_nC_x\cdot p^x\cdot (1-p)^{(n-x)}

Where _nC_x is the number of different combinations of x success in n trials.

            _nC_x=\frac{x!}{n!(n-x)!}

Hence,

            P(X=4)=_9C_4\cdot (0.5)^4\cdot (0.5)^{5}

                                _9C_4=\frac{4!}{9!(9-4)!}=126

            P(X=4)=126\cdot (0.5)^4\cdot (0.5)^{5}=0.03125

<em><u>b) Probability that at most 3 flights are on time</u></em>

The probability that at most 3 flights are on time is equal to the probabiity that exactly 0 or exactly 1 or exactly 2 or exactly 3 are on time:

         P(X\leq 3)=P(X=0)+P(X=1)+P(X=2)+P(X=3)

P(X=0)=(0.5)^9=0.00195313 . . . (the probability that all are not on time)

P(X=1)=_9C_1(0.5)^1(0.5)^8=9(0.5)^1(0.5)^8=0.00390625

P(X=2)=_9C_2(0.5)^2(0.5)^7=36(0.5)^2(0.5)^7=0.0078125

P(X=3)= _9C_3(0.5)^3(0.5)^6=84(0.5)^3(0.5)^6=0.015625

P(X\leq 3)=0.00195313+0.00390625+0.0078125+0.015625=0.02929688\\\\  P(X\leq 3) \approx 0.0293

<em><u>c) Probability that at least 8 flights are on time </u></em>

That at least 8 flights are on time is the same that at most 1 is not on time.

That is, 1 or 0 flights are not on time.

Then, it is easier to change the successful event to not being on time, so I will change the name of the variable to Y.

          P(Y=0)=_0C_9(0.5)^0(0.5)^9=0.00195313\\ \\ P(Y=1)=_1C_9(0.5)^1(0.5)^8=0.0039065\\ \\ P(Y=0)+P(Y=1)=0.00585938\approx 0.00586

6 0
4 years ago
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