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3 years ago

Can someone plz help? I do not understand

Mathematics

1 answer:

Slav-nsk [51]3 years ago

4 0

Answer:

y=x no

y=12x yes

y=1.6x yes

y=3/(4x) no

y=2x+1 no

y=3+x no

Step-by-step explanation:

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Can someone explain the process getting from:

spin [16.1K]

$\rm 5=e^{3b}$

The unknown b is stuck in the exponent position.
We can can fix that by using logarithms.
Log is the inverse operation of the exponential.

We'll take log of each side.
Log of what base tho?

Well, the base of our exponential is e,
so we'll take log base e of each side.

$\rm log_e(5)=log_e(e^{3b})$

We'll apply one of our log rules next:
$\rm \log(x^y)=y\cdot\log(x)$

This allows us to take the exponent out of the log,

$\rm log_e(5)=(3b)log_e(e)$

Another thing to remember about logs:
When the base of the log matches the inside of the log,
then the whole thing is simply 1,
$\rm log_{10}(10)=1$
$\rm log_5(5)=1$
$\rm log_e(e)=1$

So our equation simplifies to this,

$\rm log_e(5)=(3b)\cdot1$

As a final step, divide both sides by 3,

$\rm \frac13log_e(5)=b$

k, hope that helps!

6 0

3 years ago

NEED HELP ASAP! WILL MARK BRAINlIEST!

vaieri [72.5K]

Answer: 105 is your sum.

7 0

3 years ago

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Try this hard Math Problem if you dare!!

Dennis_Churaev [7]

Answer:

a. $(x - 3)^2 + 16$

b. $8(x -7)^2$

c. $(a^2 - 1)(7x - 6)$ or $(a+1)(a-1)(7x-6)$

d. $(x^2-4)(x^2+3)$ or $(x-2)(x+2)(x^2+3)$

e. $(a^n+b^n)(a^n-b^n)(a^{2n} +b^{2n})$

Step-by-step explanation:

$a.\ (x + 1)^2 - 8(x - 1) + 16$

Expand

$(x + 1)(x + 1) - 8(x - 1) + 16$

Open brackets

$x^2 + x + x + 1 - 8x + 8 + 16$

$x^2 + 2x + 1 - 8x + 24$

Collect Like Terms

$x^2 + 2x - 8x+ 1 + 24$

$x^2 - 6x+ 25$

Express 25 as 9 + 16

$x^2 - 6x+ 9 + 16$

Factorize:

$x^2 - 3x - 3x + 9 + 16$

$x(x -3)-3(x - 3) + 16$

$(x - 3)(x - 3) + 16$

$(x - 3)^2 + 16$

$b.\ 8(x - 3)^2 - 64(x-3) + 128$

Expand

$8(x - 3)(x - 3) - 64(x-3) + 128$

$8(x^2 - 6x+ 9) - 64(x-3) + 128$

Open Brackets

$8x^2 - 48x+ 72 - 64x+192 + 128$

Collect Like Terms

$8x^2 - 48x - 64x+192 + 128+ 72$

$8x^2 -112x+392$

Factorize

$8(x^2 -14x+49)$

Expand the expression in bracket

$8(x^2 -7x-7x+49)$

Factorize:

$8(x(x -7)-7(x-7))$

$8((x -7)(x-7))$

$8(x -7)^2$

$c.\ 7a^2x - 6a^2 - 7x + 6$

Factorize

$a^2(7x - 6) -1( 7x - 6)$

$(a^2 - 1)(7x - 6)$

The answer can be in this form of further expanded as follows:

$(a^2 - 1^2)(7x - 6)$

Apply difference of two squares

$(a+1)(a-1)(7x-6)$

$d.\ x^4 - x^2 - 12$

Express $x^4$ as $x^2$

$(x^2)^2 - x^2 - 12$

Expand

$(x^2)^2 +3x^2- 4x^2 - 12$

$x^2(x^2+3) -4(x^2+3)$

$(x^2-4)(x^2+3)$

The answer can be in this form of further expanded as follows:

$(x^2-2^2)(x^2+3)$

Apply difference of two squares

$(x-2)(x+2)(x^2+3)$

$e.\ a^{4n} -b^{4n}$

Represent as squares

$(a^{2n})^2 -(b^{2n})^2$

Apply difference of two squares

$(a^{2n} -b^{2n})(a^{2n} +b^{2n})$

Represent as squares

$((a^{n})^2 -(b^{n})^2)(a^{2n} +b^{2n})$

Apply difference of two squares

$(a^n+b^n)(a^n-b^n)(a^{2n} +b^{2n})$

6 0

3 years ago

Which of the following is the quotient of the rational

Alona [7]

Answer:

It is A

Step-by-step explanation:

We you divide, you multiply the reporical of the second term for example when I say

$2 \div 3$

I also mean

$2 \times \frac{1}{3}$

So it is the same concept but in more complicated way

$\frac{4x}{2x - 1} \div \frac{3x + 2}{x + 5}$

You flip the second term

$\frac{4x}{2x - 1} \times \frac{x + 5}{3x + 2}$

Then you multiply the numerator and you will get

$4x {}^{2} + 20x$

Which is found in A,but you will need to multiply the denominator in case if the choices have the same numerator

The denominator. Equals to

$6x ^{2} + x - 2$

5 0

3 years ago

What is the square root of 9

erica [24]

The square root of 9 is 3.

8 0

3 years ago

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