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spayn [35]
3 years ago
5

A coin is resting on the bottom of an empty container. The container is then fi lled to the brim three times, each time with a d

iff erent liquid. An observer (in air) is directly above the coin and looks down at it. With liquid A in the container, the apparent depth of the coin is 7 cm, with liquid B it is 6 cm, and with liquid C it is 5 cm. Rank the indices of refraction of the liquids in descending order (largest fist).
a. nC, nA, nB
b. nA, nB, nC
c. nB, nA, nC
d. nC, nB, nA
e. nA, nC, nB
Physics
1 answer:
ahrayia [7]3 years ago
3 0

when we placed in the container of real depth assuming = d

if the container filled with liquid A then its apparent depth d' = 7cm

so the refractive index nA = real depth / apparent depth

                                       = d/7cm = 0.1428d

if the container filled with liquid B then its apparent depth d' = 6cm

so the refractive index nB = real depth / apparent depth

                                       = d/6cm = 0.166d

if the container filled with liquid C then its apparent depth d' = 5cm

so the refractive index nC = real depth / apparent depth

                                       = d/5cm = 0.2d

Since the refractive index is inversely proportional to the apparent depth

then the refractive indices are nC > nB > nA

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A glider of mass 0.170 kg moves on a horizontal frictionless air track. It is permanently attached to one end of a massless hori
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Answer:

Answer:

a.  1.594 m/s = v

b. 1.274 m/s = v

Explanation:

A) First calculate the potential energy stored in the spring when it is compressed by 0.180 m...

U = 1/2 kx²

Where U is potential energy (in joules), k is the spring constant (in newtons per meter) and x is the compression (in meters)

U = 1/2(13.0 N/m)(0.180 m)² = 0.2106 J

So when the spring passes through the rest position, all of its potential energy will have been converted into kinetic energy.  K = 1/2 mv².

 0.2106 J  = 1/2(0.170 kg kg)v²

0.2106 J  = (0.0850 kg)v²

2.808m²/s² = v²

1.594 m/s = v

(B)  When the spring is 0.250 m from its starting point, it is 0.250 m - 0.180 m = 0.070 m past the equilibrium point.  The spring has begun to remove kinetic energy from the glider and convert it back into potential.  The potential energy stored in the spring is:

U = 1/2 kx² = 1/2(13.0 N/m)(0.070 m)² = 0.031J

Which means the glider now has only 0.2106 J  - 0.031J = 0.1796 J of kinetic energy remaining.

K = 1/2 mv²

0.1796 J = 1/2(0.170 kg)v²

0.138 J = (0.0850 kg)v²

1.623 m²/s² = v²

1.274 m/s = v

5 0
3 years ago
The radar gun measures the frequency of the radar pulse echoing off your car. By what percentage is the measured frequency diffe
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Question: A. The state highway patrol radar guns use a frequency of 9.15 GHz. If you're approaching a speed trap driving 30.1 m/s, what frequency shift will your FuzzFoiler 2000 radar detector see?

B. The radar gun measures the frequency of the radar pulse echoing off your car. By what percentage is the measured frequency different from the original frequency? (Enter a positive number for a frequency increase, negative for a decrease. Just enter a number, without a percent sign.)?

Answer:

The frequency change percentage is 9.94%

Explanation:

The frequency shift can be calculated as follows.

F= \frac{V+V_{0}}{V+V_{s}}

   = 9.05GHz\times\frac{343m/s+0}{343m/s+(-31.3m/s)}

   =9.95 GHz

So the frequency change seen by the detector is 9.95 - 9.05

% difference= \frac{0.9}{9.05} \times100

                    = 9.94%

3 0
3 years ago
3. A car does an emergency stop from 144 km\h in 4s<br> What was its deceleration?
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Answer:

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Explanation:

5 0
3 years ago
Please Help Me!
balandron [24]

The image distance when a boy holds a toy soldier in front of a concave mirror, with a focal length of 0.45 m. is -0.56 m.

<h3>What is image distance?</h3>

This is the distance between the image formed and the focus when an object is placed in front of a plane mirror.

To calculate the image distance, we use the formula below.

Formula:

  • 1/f = 1/u+1/v........... Equation 1

Where:

  • f = Focal length of the mirror
  • v = Image distance
  • u = object distance

From the question,

Given:

  • f = 0.45 m
  • u = 0.25 m

Substitute these values into equation 1 and solve for the image distance

  • 1/0.45 = 1/0.25 + 1/v
  • 2.22 = 4+1/v
  • 1/v = 2.22-4
  • 1/v = -1.78
  • v = 1/(-1.78)
  • v = -0.56 m

Hence, The image distance is -0.56 m.

Learn more about image distance here: brainly.com/question/17273444

5 0
2 years ago
A scientist examines a large pot of boiling water and a small cup of boiling water. The scientist determines that the large pot
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Answer:

d. The large pot of water and small cup of water have the same temperature, but the large pot of water has higher thermal energy.

Explanation:

Temperature is a measure of the average kinetic energy of individual molecules. While internal energy refers to the total kinetic energy of the molecules within the object. Since in this case we have the same amount of average kinetic energy, then the large pot of water and small cup of water have the same temperature. While the large pot of water has higher thermal energy, since has more water particles than the small cup.

7 0
3 years ago
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