Wouldn't mass stay the same and acceleration increase or am I mistaken?
Spring C stretches 100 cm.
Explanation:
The spring constant is simply the stiffness of the spring. The higher the spring constant the more stiff the spring is.
Spring constant shows the force needed to stretch a spring from it's equilibrium position. If a material requires more force to cause it to stretch, it will have a high spring constant.
According to hooke's law "the force needed to extended an elastic material is directly proportional to its extension"
F = ke
k is the spring constant
e is the extension
We see that the spring that stretches by 100 is the less stiff compared to other springs. It has the smallest spring constant.
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Answer:81.235N
Explanation:
Work=88J
theta=10°
distance=1.1 meters
work=force x cos(theta) x distance
88=force x cos10 x 1.1 cos10=0.9848
88=force x 0.9848 x 1.1
88=force x 1.08328
Divide both sides by 1.08328
88/1.08328=(force x 1.08328)/1.08328
81.235=force
Force=81.235
Answer:
5.025 atm
Change the 2.01 to ml then cross multiply
400/1= 2010/x
210/400=5.025
Answer:
9.17 m/s^2
Explanation:
Formula for force is given by
F = m*a
where F is the force in newton
m is the mass of body in KG
and
a is the acceleration of body on m/s^2
_______________________________________________
Given
F = 11,000
mass = 1,200 Kg
we have to find value of acceleration
using
F = m*a
11,000 = 1200*a
=> a = 11,000 /1200 = 9.17
Thus, the acceleration of a car is 9.17 meter per second square