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spayn [35]
3 years ago
5

A coin is resting on the bottom of an empty container. The container is then fi lled to the brim three times, each time with a d

iff erent liquid. An observer (in air) is directly above the coin and looks down at it. With liquid A in the container, the apparent depth of the coin is 7 cm, with liquid B it is 6 cm, and with liquid C it is 5 cm. Rank the indices of refraction of the liquids in descending order (largest fist).
a. nC, nA, nB
b. nA, nB, nC
c. nB, nA, nC
d. nC, nB, nA
e. nA, nC, nB
Physics
1 answer:
ahrayia [7]3 years ago
3 0

when we placed in the container of real depth assuming = d

if the container filled with liquid A then its apparent depth d' = 7cm

so the refractive index nA = real depth / apparent depth

                                       = d/7cm = 0.1428d

if the container filled with liquid B then its apparent depth d' = 6cm

so the refractive index nB = real depth / apparent depth

                                       = d/6cm = 0.166d

if the container filled with liquid C then its apparent depth d' = 5cm

so the refractive index nC = real depth / apparent depth

                                       = d/5cm = 0.2d

Since the refractive index is inversely proportional to the apparent depth

then the refractive indices are nC > nB > nA

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There are four springs stretched by the same mass.
brilliants [131]

Spring C stretches 100 cm.

Explanation:

The spring constant is simply the stiffness of the spring. The higher the spring constant the more stiff the spring is.

Spring constant shows the force needed to stretch a spring from it's equilibrium position. If a material requires more force to cause it to stretch, it will have a high spring constant.

          According to hooke's law "the force needed to extended an elastic material is directly proportional to its extension"

          F = ke

   k is the spring constant

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We see that the spring that stretches by 100 is the less stiff compared to other springs. It has the smallest spring constant.

Learn more;

Force brainly.com/question/8882476

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8 0
3 years ago
how much force would be required to produce 88 j of work when pushing a box 1.1meters at an angle of 10 degrees?
ycow [4]

Answer:81.235N

Explanation:

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theta=10°

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work=force x cos(theta) x distance

88=force x cos10 x 1.1 cos10=0.9848

88=force x 0.9848 x 1.1

88=force x 1.08328

Divide both sides by 1.08328

88/1.08328=(force x 1.08328)/1.08328

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5 0
3 years ago
The volume of a gas at 400.0ml when the pressure is 1.00atm. at the same temperature, what is the pressure at which the volume o
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Answer:

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3 years ago
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Answer:

9.17 m/s^2

Explanation:

Formula for force is given by

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where F is the force in newton

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_______________________________________________

Given

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11,000 = 1200*a

=> a = 11,000 /1200 = 9.17

Thus, the acceleration of a car is 9.17 meter per second square

5 0
3 years ago
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