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2 years ago

A bat emits a pulse of sound of wavelength 0.0085 m. Calculate the frequency of the sound.

Physics

2 answers:

alina1380 [7]2 years ago

7 0

Answer:

v = 4.0 10⁴ Hz

Explanation:

The bat emits sound in the air, so we can use the speed of sound in air

v = 344 m / s

also the expression that relates the wavelength and frequency with the speed of the wave

v = λ f

f = v / λ

let's calculate

v = 344/0.0085

v = 4.0 10⁴ Hz

MissTica2 years ago

5 0

HI thts way tooo much to answer but ye...d;

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olchik [2.2K]

Answer:

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3 years ago

Calculate net force 532N 215N

lorasvet [3.4K]

Answer:

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3 years ago

A cat pushes a mouse horizontally on a frictionless floor with a net force of 1.0 N 1.0N1, point, 0, start text, N, end text for

vesna_86 [32]

Answer: 3

Explanation:

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3 years ago

The photon energies used in different types of medical x-ray imaging vary widely, depending upon the application. Single dental

pav-90 [236]

A) $5.0\cdot 10^{-11} m$

The energy of an x-ray photon used for single dental x-rays is

$E=25 keV = 25,000 eV \cdot (1.6\cdot 10^{-19} J/eV)=4\cdot 10^{-15} J$

The energy of a photon is related to its wavelength by the equation

$E=\frac{hc}{\lambda}$

where

$h=6.63\cdot 10^{-34}Js$ is the Planck constant

$c=3\cdot 10^8 m/s$ is the speed of light

$\lambda$ is the wavelength

Re-arranging the equation for the wavelength, we find

$\lambda=\frac{hc}{E}=\frac{(6.63\cdot 10^{-34} Js)(3\cdot 10^8 m/s)}{4\cdot 10^{-15}J}=5.0\cdot 10^{-11} m$

B) $2.0\cdot 10^{-11} m$

The energy of an x-ray photon used in microtomography is 2.5 times greater than the energy of the photon used in part A), so its energy is

$E=2.5 \cdot (4\cdot 10^{-15}J)=1\cdot 10^{-14} J$

And so, by using the same formula we used in part A), we can calculate the corresponding wavelength:

$\lambda=\frac{hc}{E}=\frac{(6.63\cdot 10^{-34} Js)(3\cdot 10^8 m/s)}{1\cdot 10^{-14}J}=2.0\cdot 10^{-11} m$

4 0

2 years ago

While playing basketball in PE class, Logan lost his balance after making a lay-up and colliding with the padded wall behind the

olga2289 [7]

Answer:

a.) F = 3515 N

b.) F = 140600 N

Explanation: given that the

Mass M = 74kg

Initial velocity U = 7.6 m/s

Time t = 0.16 s

Force F = change in momentum ÷ time

F = (74×7.6)/0.16

F = 3515 N

b.) If Logan had hit the concrete wall moving at the same speed, his momentum would have been reduced to zero in 0.0080 seconds

Change in momentum = 74×7.6 + 74×7.6

Change in momentum = 562.4 + 562.4 = 1124.8 kgm/s

F = 1124.8/0.0080 = 140600 N

6 0

3 years ago

A bat emits a pulse of sound of wavelength 0.0085 m. Calculate the frequency of the sound. ​

A bat emits a pulse of sound of wavelength 0.0085 m. Calculate the frequency of the sound.