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pentagon [3]
3 years ago
8

A bat emits a pulse of sound of wavelength 0.0085 m. Calculate the frequency of the sound. ​

Physics
2 answers:
alina1380 [7]3 years ago
7 0

Answer:

   v = 4.0 10⁴ Hz

Explanation:

The bat emits sound in the air, so we can use the speed of sound in air

          v = 344 m / s

also the expression that relates the wavelength and frequency with the speed of the wave

          v = λ f

          f = v / λ

let's calculate

          v = 344/0.0085

          v = 4.0 10⁴ Hz

MissTica3 years ago
5 0

HI thts way tooo much to answer but ye...d;

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A force of 30.0 N is applied to a 3.00 kg object for 3.00 seconds. Calculate the velocity experienced by the object.
olganol [36]

Answer:

Explanation:

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3 years ago
What is the pendulum length whose period is 2.0s ?
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 \frac{T}{2 \pi } = \sqrt{ \frac{L}{g} }|square\\
 \frac{T^2}{2 \pi }  = \frac{L}{g} \\
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7 0
3 years ago
Give examples of not useful high friction
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Friction can be bad by being too strong or too weak. 

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6 0
3 years ago
At one instant, the center of mass of a system of two particles is located on the x-axis at 2.0 cm and has a velocity of (5.0 m/
Nata [24]

Answer:

Explanation:

Given that,

At one instant,

Center of mass is at 2m

Xcm = 2m

And velocity =5•i m/s

One of the particle is at the origin

M1=? X1 =0

The other has a mass M2=0.1kg

And it is at rest at position X2= 8m

a. Center of mass is given as

Xcm = (M1•X1 + M2•X2) / (M1+M2)

2 = (M1×0 + 0.1×8) /(M1 + 0.1)

2 = (0+ 0.8) /(M1 + 0.1)

Cross multiply

2(M1+0.1) = 0.8

2M1 + 0.2 =0.8

2M1 = 0.8-0.2

2M1 = 0.6

M1 = 0.6/2

M1 = 0.3kg

b. Total momentum, this is an inelastic collision and it momentum after collision is given as

P= (M1+M2)V

P = (0.3+0.1)×5•i

P = 0.4 × 5•i

P = 2 •i kgm/s

c. Velocity of particle at origin

Using conversation of momentum

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P(before) = P(after)

0.3V1 = 2 •i

V1 = 2/0.3 •i

V1 = 6 ⅔ •i m/s

V1 = 6.667 •i m/s

4 0
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