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3 years ago

Does a stove have mechanical energy

1 answer:

6 0

-- Any object has gravitational potential energy relative to any place
lower than where the object is. The stove in the kitchen has potential
energy relative to the basement floor.

-- If an object is not moving, then it has no kinetic energy. The stove has
no kinetic energy unless you throw it or drop it out of a window.

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a ball thrown vertically downwatd stikes a horizontal surface with a speed of 15 meters per seconds if then bounces and reaches

Anna71 [15]

but why was it thrown is the real question

3 0

3 years ago

As an electron approaches a proton, the electron's force of attraction...

Tems11 [23]

Answer: B. Increases

Explanation:

An electron is a negatively charged particle, while a proton is positively charged.

Opposites attract so as it approaches the proton the force of attraction will increase.

7 0

3 years ago

A charged particle decelerates as it moves from location a to location b. if va = 160 v and vb = 100 v, what is the sign of the

skelet666 [1.2K]

The sign of the charged particle is positively charged.

<h3>What is potential difference?</h3>

When a single charge is transported in an electric field, work is done by the potential difference (also known as electrical potential).
There is potential energy stored in this charge that could flow when work is done on it.
Voltage is the possibility of a single charge flowing. The need to flow increases with voltage.
Here, voltage can be the potential differences.

The potential difference between the 2 points determines the movement of that particle. An electron moves from lower to higher potential which is negatively charged, and a positively charged particle moves from higher to lower potential.

Now, since the particle is moving from a point A having 160 v potential to point B having 100 v potential that is it is moving from higher potential to a lower potential therefore the particle will be a positively charged one.

Learn more about potential difference,

brainly.com/question/23716417

#SPJ1

3 0

1 year ago

A small block of mass M = 0.10 kg is released from rest at point 1 at a height H = 1.8 m above the bottom of a track, as shown i

Ede4ka [16]

Answer:

Explanation:

A) is not correct, because the gravitation potential energy will depend on the height the block is located at. It will be calculated with the formula:

U=mgh.

If we take the ground as a zero height reference, then on point 2 the potential energy will be:

$U_{2} = 0.10kg(9.81 m/s^{2})(0.6m)$

$U_{2}=0.59 J$

While on point 3, the potential energy will be greater.

$U_{3}=0.10kg(9.81 m/s^{2})(1.2m)$

$U_{3}=1.18 J$

B) is not the right answer because the kinetic energy will vary with the height the block is located at in the fact that the energy is conserved (this is if we don't take friction into account or air resistance) so in this case:

$U_{2}+K_{2}= U_{3}+K_{3}$

We already know the potential energy at point 2. We can calculate the kinetic energy at point 3 like this:

$K_{3} =\frac{1}{2}mv_{3}^{2}$

$K_{3} =\frac{1}{2}(0.10kg)(2.5 m/s)^{2}$

$K_{3} =0.31 J$

So the kinetic energy at point 2 is given by the equation:

$K_{2} =U_{3}-U_{2}+K_{3}$

so:

$K_{2} = (1.18J)-(0.59J)+0.31J$

$K_{2} =0.9J$

As you may see the kinetic energy at point 2 is greater than the kinetic energy at point 3.

C) Is not correct because according to the first law of thermodinamics, energy is not lost, only transformed. So, since we are not taking into account friction or any other kind of loss, then we can say that the amount of mechanical energy at point 1 is exactly the same as the mechanical energy at point 3.

D) Because of what we talked about on part C, this will be the true situation, because the mechanical energy of the block will be the same no matter theh point you measure it at.

7 0

3 years ago

A cord is wrapped around the rim of a solid uniform wheel 0.300 m in radius and of mass 8.00 kg. A steady horizontal pull of 34.

disa [49]

Answer:

A. α = 94.4 rad/s

B. a = 28.32 m/s

C. N = 34N

D. α = 94.4 rad/s

a = 28.32 m/s

N = 44.4 N

Explanation:

part A:

using:

∑T = Iα

where T is the torque, I is the moment of inertia and α is the angular momentum.

firt we will find the moment of inertia I as:

I = $\frac{1}{2}MR^2$

Where M is the mass and R is the radius of the wheel, then:

I = $\frac{1}{2}(8 kg)(0.3 m)^2$

I = 0.36 kg*m^2

Replacing on the initial equation and solving for α, we get::

∑T = Iα

Fr = Iα

34 N = 0.36α

α = 94.4 rad/s

part B

we need to use this equation :

a = αr

where a is the aceleration of the cord that has already been pulled off and r is the radius of the wheel, so replacing values, we get:

a = (94.4)(0.3 m)

a = 28.32 m/s

part C

Using the laws of newton, we know that:

N = T

where N is the force that the axle exerts on the wheel part and T is the tension of the cord

so:

N = 34N

part D

The anly answer that change is the answer of the part D, so, aplying laws of newton, it would be:

-Mg + N +T = 0

Then, solving for N, we get:

N = -T+Mg

N = -34 + (8 kg)(9.8)

N = 44.4 N

6 0

3 years ago