Answer:
B. 0.98 m/s
Explanation:
This is because we use the simple formula of dividing the distance by the time. In which case would be 13.69m (distance) divided by 13.92s (time) and we will get 0.983477011 or 0.98m/s (your answer)
I hope this made sense and hoped it helped. Good luck with your test luv :)
Answer:
I think the most interesting 3rd century 3g durga was 5f5
Explanation:
I 50degree and I have not done a good morning mam sushant since I am not pregnant and have no
Answer:
Magnitude = 4.056 m
Direction = 42.3⁰
Explanation:
The vector is resolved in terms of the vertical and horizontal components. Let's look each of these separately.
The vector 4.40 is directed East. This automatically becomes a horizontal component.
But we know that there is a vector 3.40 North West. The angle the vector makes with the horizontal is 61⁰.
Resolving the vectors should yield the horizontal and vertical components:
Horizontal components
The first component is 4.40 m
The second one is derived by resolving 3.40 to the horizontal like this 3.40 × - cos 61⁰ = -1.648 m
Adding the horizontal component gives 4.40 m + ( -1.648 m) = 2.752 m
Vertical components
Resolve 3.40 with the angle 61⁰ like this: vertical comp = 3.41 × sin 61
= 2.98 m
The magnitude is given by √[(2.98)²+ (2.752)²] = 4.056 m Ans
The direction us given by tan⁻¹ (2.98/2.752) = 42.3⁰ Ans
Answer:
At 11.5 m
Explanation:
The power per unit area corresponds to the intensity, which is given by

where
P is the power
is the area irradiated at a distance r from the source (it corresponds to the surface area of a sphere of radius r)
Here we want the intensity of the two light bulbs to be the same, so

where we have
P1 = 100 W is the power of the first light bulb
P2 = 75 W is the power of the second light bulb
r2 = 10 m is the distance from the second light bulb
Solving for r1, we find

Answer:
v = 10.84 m/s
Explanation:
using the equation of motion:
v^2 = (v0)^2 + 2×a(r - r0)
<em>due to the hammer starting from rest, vo = 0 m/s and a = g , g is the gravitational acceleration.</em>
v^2 = 2×g(r - r0)
v = \sqrt{2×(-9.8)×(4 - 10)}
= 10.84 m/s
therefore, the velocity at r = 4 meters is 10.84 m/s