Answer:
-19
Step-by-step explanation:
0.3h+1.2=0.1h-2.6
.2h+1.2=-2.6
.2h=-3.8
h=-19
For this case we first calculate the rate in blocks per minutes.
rate = (15.5) / (35) = 0.443 blocks per minutes.
Then, we can go to blocks per hour.
Remember: 1h = 60min.
rate = 0.443 * (1/60) = 0.00738 blocks per hour.
answer
his rate in blocks per hour is 0.00738 blocks per hour.
Answer:
line QR
Step-by-step explanation:
Plane QRB is the front face. Plane TSR is the top face. The planes intersect at the top front edge, line QR.
Answer:
The car must have a speed of 25 kilometres per hour to stop after moving 7 metres.
Step-by-step explanation:
Let be 
, where 
is the stopping distance measured in metres and 
is the speed measured in kilometres per hour. The second-order polynomial is drawn with the help of a graphing tool and whose outcome is presented below as attachment.
The procedure to find the speed related to the given stopping distance is described below:
1) Construct the graph of 
.
2) Add the function 
.
3) The point of intersection between both curves contains the speed related to given stopping distance.
In consequence, the car must have a speed of 25 kilometres per hour to stop after moving 7 metres.
Answer:
60 ft³
Step-by-step explanation:
2 x 3 x 4 = 24
3 x 3 x (6-2) = 36
24 + 36 = 60
hope this helps :)
