Answer:
(19 , -14)
Step-by-step explanation:
Find the distance in between each x & y for a coordinate.
Let: (x₁ , y₁) = (-1 , 2)
Let: (x₂ , y₂) = (9 , -6)
From x₁ ⇒ x₂: 9 - (-1) = 10
From y₁ ⇒ y₂: -6 - 2 = -8 = 8*
*Remember that distance cannot be negative, but for the sake of this question, we will leave it as -8.
The distance between the x points are in intervals of 10. The distance between the y points are in intervals of 8. Add 10 & subtract 8 to their respective numbers to get endpoint 2:
(9 (+ 10) , -6 (- 8)) = (19 , -14)
Endpoint 2 = (19 , -14)
~
The question was incorrect. Please find the correct content below.
Compare 32/35 and 9/10.
Comparing 32/35 and 9/10 we have 32/35 is greater than 9/10, that is 32/35 > 9/10.
Fraction is the ratio of two numbers. The upper number is called Numerator and the Lower number is called the Denominator.
We know that if the denominators are the same for two fractions then which has the greatest numerator is a greater fraction than the other.
Given the fractions are 32/35, 9/10
To compare this two fractions we have to make denominators equal first.
LCM of 10,35 = 70
Calculating the fractions,
32/35 = (32*2)/(35*2) = 64/70
9/10 = (9*7)/(10*7) = 63/70
Since 64 > 63
So 64/70 > 63/70
Therefore, 32/35 > 9/10
Hence fraction 32/35 is greater than the other fraction 9/10.
Learn more about Fraction here -
brainly.com/question/78672
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Hi Natalie
We have x/4 = 9
All you have to do is cross multiplication
x = 4*9
x= 36
That's all :)
I hope that's help:)
Now if you wanna check my answer just replace x by 36
36/4 = 9
9= 9
Because when you divide 36 by 4 you will find 9
I hope that's help:)
Answer:

Step-by-step explanation:
Using the rule of exponents
⇔
, then
=
= 
There are 60 students. The winner got 70% of the 60 students votes. Let's work this one out to get the answer.
First, you need to figure out what 70% of 60 is, by using this equation.
60 x .70 = 42.
Now that you know the answer is 42, you now know that 70 percent of 60 is 42.
So, the class president got 42 winning votes!
Hope I could help!
Ossashi(づᵔᗜᵔ)づ