Assuming T, B and N are all on the same line, then we can say
BT + TN = BN
which is the segment addition postulate.
Subtract TN from both sides to get
BT + TN = BN
BT + TN - TN = BN - TN
BT = BN - TN
BN - TN = BT
Which is what choice C is saying. Therefore the answer is choice C.
The ar. of square =X^
=5.76
So,X=√5.76
=2.4
now, perimeter of square =4(X)
=4(2.4)
=9.6
So, the perimeter of the square is 9.6cm..
Thanks!
Hope it helps you..
Part A:
Consider from x = -5 to x = -4, they are 1 unit apart and the difference of their outputs is given by:
-3 - (-11) = -3 + 11 = 8.
Thus, the value of the output increases by 8 units for each one unit increase in the input.
Part B:
Consider from x = -3 to x = -1, they are 2 units apart and the difference of their outputs is given by:
21 - 5 = 16.
Thus, the value of the output increases by 16 units for each two units increase in the input.
Part C:
Consider from x = 0 to x = 3, they are 3 units apart and the difference of their outputs is given by:
53 - 29 = 24.
Thus, the value of the output increases by 24 units for each three units increase in the input.
Part D:
It can be noticed that the ratio difference in the outputs to the input intervals are equal for all the given input intervals.
i.e 8 / 1 = 16 / 2 = 24 / 3.
Answer:
1.666666666666667
Step-by-step explanation:
5/3
= 1.666666666666667
