I like math so i think it's good for me
Answer:
(1)The value of x is -9 .
Option (B) is correct .
(2)The value of x is 13 .
Option (A) is correct .
(3)The value of the x is 11 .
Option (D) is correct .
(4) The value of the x is -15 .
Option (A) is correct .
(5)The value of the x is -11 .
Option (C) is correct .
Step-by-step explanation:
First Part
As given
4x = -36

x = -9
Therefore the value of x is -9 .
Option (B) is correct .
Second Part
As given
5x - 15 = 50
5x = 50 + 15gg
5x = 65

x = 13
Therefore the value of x is 13 .
Option (A) is correct .
As given
4(x+2)-17=35
4x + 8 - 17 = 35
4x = 35 + 17 - 8
4x = 44

x = 11
Therefore the value of the x is 11 .
Option (D) is correct .
Fourth Part
As given
6x+12=4x-18
6x-4x = -12-18
2x = -30

x = -15
Therefore the value of the x is -15 .
Option (A) is correct .
Fifth Part
As given

Simplify the above
4x-10+5×2 = 2x-22
4x-10+10= 2x-22
4x-2x = -22
2x=-22

x = -11
Therefore the value of the x is -11 .
Option (C) is correct .
Answer:
Use the distance formula to determine the distance between the two points.
Distance
=
√(x2−x1)^2 + (y2−y1)^2
Substitute the actual values of the points into the distance formula.
√ ( (−6) − 0)^2 +( (−3) − 4)^2
Subtract 0 from −6
√(−6)^2 + ( ( −3 ) −4 )^2
Raise −6 to the power of 2
√36 + ( ( −3 ) −4 )^2
Subtract 4 from −3
√36 + ( −7 )^2
Raise −7 to the power of 2
√ 36 + 49
Add 36 and 49
√85
Answer:
No mode.
Step-by-step explanation:
No mode.
None of the numbers repeat and since the mode is the most frequent number there isn't one.
The maximum height the ball achieves before landing is 682.276 meters at t = 0.
<h3>What are maxima and minima?</h3>
Maxima and minima of a function are the extreme within the range, in other words, the maximum value of a function at a certain point is called maxima and the minimum value of a function at a certain point is called minima.
We have a function:
h(t) = -4.9t² + 682.276
Which represents the ball's height h at time t seconds.
To find the maximum height first find the first derivative of the function and equate it to zero
h'(t) = -9.8t = 0
t = 0
Find second derivative:
h''(t) = -9.8
At t = 0; h''(0) < 0 which means at t = 0 the function will be maximum.
Maximum height at t = 0:
h(0) = 682.276 meters
Thus, the maximum height the ball achieves before landing is 682.276 meters at t = 0.
Learn more about the maxima and minima here:
brainly.com/question/6422517
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