<span><span>13−<span>6x</span></span>=<span><span><span>(<span><span>2x</span>−5</span>)</span>2</span>+3</span></span>Step 1: Simplify both sides of the equation.<span><span><span>−<span>6x</span></span>+13</span>=<span><span><span>4<span>x2</span></span>−<span>20x</span></span>+28</span></span>Step 2: Subtract 4x^2-20x+28 from both sides.<span><span><span><span>−<span>6x</span></span>+13</span>−<span>(<span><span><span>4<span>x2</span></span>−<span>20x</span></span>+28</span>)</span></span>=<span><span><span><span>4<span>x2</span></span>−<span>20x</span></span>+28</span>−<span>(<span><span><span>4<span>x2</span></span>−<span>20x</span></span>+28</span>)</span></span></span><span><span><span><span>−<span>4<span>x2</span></span></span>+<span>14x</span></span>−15</span>=0</span>Step 3: Use quadratic formula with a=-4, b=14, c=-15.<span>x=<span><span><span>−b</span>±<span>√<span><span>b2</span>−<span><span>4a</span>c</span></span></span></span><span>2a</span></span></span><span>x=<span><span><span>−<span>(14)</span></span>±<span>√<span><span><span>(14)</span>2</span>−<span><span>4<span>(<span>−4</span>)</span></span><span>(<span>−15</span>)</span></span></span></span></span><span>2<span>(<span>−4</span>)</span></span></span></span><span>x=<span><span><span>−14</span>±<span>√<span>−44</span></span></span><span>−<span>8</span></span></span></span>
Answer:
All angles that are either exterior angles, interior angles, alternate angles or corresponding angles are all congruent. The picture above shows two parallel lines with a transversal. The angle 6 is 65°. Is there any other angle that also measures 65° hope this helps you
Step-by-step explanation:
Answer:
I think 3 ............................three
Answer:
Group 2
Step-by-step explanation:
Because in group 2 they have more 46 year old tourists so it is most likely that the random 46 year old belongs to group 2.
Answer:
5abc^2/35a^3c^3
Step-by-step explanation:
To bring the fraction: b/7a^2c to a denominator of 35a^3c^3, find the dividend when the 35a^3c^3 is divided by 7a^2c
=35a^3c^3/ 7a^2c
Recall that
a^x/a^y = a^x-y
Hence
35a^3c^3/ 7a^2c = 5a^3-2c^3-1
= 5ac^2
Now multiply the numerator and denominator by the result
b/7a^2c = (b * 5ac^2)/(7a^2c * 5ac^2)
Recall that
a^x * a^y = a^x+y
Hence
b/7a^2c = (b * 5ac^2)/(7a^2c * 5ac^2) = 5abc^2/35a^3c^3
