Calculate the probability that both bids are successful
Answer:
The probability that both contracs are successful is 0.21
Step-by-step explanation:
Given
E1 = the event that the bid on the first contract is successful
E2 = the event that the bid on the second contract is successful
P(E1) = 0.3
P(E2) = 0.7
Let P(A) represent the event that both contracts are successful
P(A) = P(E1 and E2)
Since both events are independent. P(A) becomes
P(A) = = P(E1 * P(E2)
By substituton
P(A) = 0.3 * 0.7
P(A) = 0.21
Hence the probability that both contracs are successful is 0.21
Answer:

Step-by-step explanation:
since its only 2/5 of 1 hour, two 2/5 equal 4/5 so we divide the 12 2/3 by 2 to find the 1/5 which is 6 1/3
÷2=


Considering the given function, the table is completed as follows:
x|y
-12|15
-6| 11
3|5
15|-3
<h3>Which is the function?</h3>
The function is defined by:

Hence, when x = -12:

When x = -6:

When x = 3:

When x = 15:

More can be learned about functions at brainly.com/question/25537936
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