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mario62 [17]
3 years ago
15

In circle D, EDH LEDG.

Mathematics
2 answers:
Tresset [83]3 years ago
6 0

Answer:

pls send thru the picture to clarify ur question, i don't get it.

MaRussiya [10]3 years ago
5 0

Answer:

hey mate

the question is not understandable

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Directions: Evaluate the following combinations and determine the value of the
Andru [333]

Answer:

1. C(9,4) : n=9, s=4

2. C(10,5) : r=5

3. C(5,5) : n=5

4. C(7,7) : n=6

5. C(18,17) : r=3

Step-by-step explanation:

4 0
3 years ago
Solve the problem by writing an inequality. A club decides to sell T-shirts for $12 as a fund-raiser. It costs $20 plus $8 per T
pashok25 [27]
<h3>Hello there i hope you are having good day :) Question : Solve the problem by writing an inequality. =  A club decides to sell T-shirts for $12 as a fund-raiser. It costs $20 plus $8 per T-shirt to make the T-shirts. Write and solve an equation to find how many T-shirts the club needs to make and sell in order to profit at least $100. Show your work? = So firstly  the each of the shirt cost $12 and the money made for the shirt equals 12$ so the cost per the shirt would be 20 + 8x that lead to needing at least 100$  amount made - cost = profit would equal to 12x - (20-8x) ≥ 100 then you would do 12x-20-8x = 100 then you would also do 4x-20 = 100 then you add 20 and add 20 again that would equal 4x/4x = 120/4  that would finally lead you to the answer that would be x = 30 --->  x ≥ 30</h3><h3>Hopefully this help you.</h3>

4 0
3 years ago
What is the result of converting 0.85 liters into milliliters
Artyom0805 [142]
The answer would be 850 milliliters.
4 0
3 years ago
Read 2 more answers
What is 8 and 7/12 times 3
Elza [17]
8\frac{7}{12} =  \frac{103}{12}
3=\frac{36}{12}

\frac{103}{12}×<span>\frac{36}{12}=</span>\frac{3708}{144}=\frac{103}{4}=23.75
7 0
3 years ago
Read 2 more answers
Calculate the volume of copper used to make a copper pipe which is 50cm long, that has an outer diameter of 8cm and a thickness
Maslowich

i know the answer but im not telling you boi

3 0
3 years ago
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