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Ann [662]
2 years ago
15

Joelle wants to have an emergency fund to cover 6 months of her expenses. Her

Mathematics
1 answer:
nikdorinn [45]2 years ago
3 0

How long will it take her to build her emergency fund is 30 months

Given:

Gross pay =$4,000

Monthly expenses =$2,000

First step is to calculate her Joelle 6 month expenses

6 months expenses=$2,000 × 6

6 months expenses= $12,000

Second step is to calculate the amount of income Joelle saved each month

Income= 10% × $4,000

Income = $400

Now let calculate how long will it take her to build her emergency fund

Number of months=$12,000/$400

Number of months=30 months

Inconclusion How long will it take her to build her emergency fund is 30 months

Learn more here:

brainly.com/question/2389537

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Suppose that the farmer had bought the rice at x dollars per bag and had sold them at a 25% markup.  How much did the bags cost him before he added the markup?  1.25x =$75 results in $75/1.25, or $60 per bag.

If he sold 25 bags, his profit would be 1.25($60/bag)(25 bags) = $1875.

I very seriously doubt that the rice was $7500 per bag.  Perhaps you meant $75/bag...?


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Select the factor pairs for the number 28. Choose ALL that apply.
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A train traveled from Station A to Station B at an average speed of 80 kilometers per hour and then from Station B to Station C
earnstyle [38]

Answer:

(i). Average speed = 75 km per hour

(ii). Average speed = 75 km per hour

Step-by-step explanation:

This question is incomplete; here is the complete question.

A train traveled from station A to station B at an average speed of 80 kilometers per hour and then from station B to station C at an average of 60 kilometers per hour. If the train did not stop at station b, what was the average speed at which the train traveled from station A to C?

(i). The distance that the train traveled from station A to station B was 4 times the distance that train traveled from station B to station C.

(ii). The amount of time it took to the train to travel from station A to station B is 3 times the amount of time that it took the train to travel from station B to station C.

(i) Let the distance between station B and station C = x km

So the distance between Station A and station B = 4x km

Therefore, time to travel the distance x km with 80 km per hour = \frac{\text{Distance traveled}}{\text{Speed}}

= \frac{4x}{80}

Similarly time taken to travel between station B and station C with speed 60 km per hour = \frac{x}{60} km per hour

Now average speed between station A and station C = \frac{\text{Total distance between station A and station C}}{\text{time taken to travel}}

= \frac{4x+x}{\frac{4x}{80}+\frac{x}{60}}

= \frac{5x}{\frac{4x}{60} }

= \frac{5\times 60}{4}

= 75 km per hour

(ii). Let the train took the time to cover the distance between station B and station C = t hours

Therefore, time taken by the train between station A and B = 3t

Distance between Station A and station B = Speed × time

= 80 × 3t

= 240t km

Similarly distance between station B and station C = 60 × t

= 60t

Now average speed between station A and station C = \frac{240t+60t}{(3t+t)}

= \frac{300t}{4t}

= 75 km per hour

4 0
3 years ago
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