The correct answer is B. This may seem tricky at first, but if you will notice how the units are marked, they are marked by 2s. Therefore the first figure moves down 5 blocks and over 4 blocks.
If Each side of an equilateral triangle<span> is 10 m. ... Thus </span>triangle<span> APC is a right</span>triangle<span>. The length of CA is 10 m, and the length of PC is 5 m, and hence you can use Pythagoras' theorem to find the length of AP, which </span>is the height<span> of the </span>triangle<span>ABC.
</span>If Each side of an equilateral triangle<span> is 10 m. ... Thus </span>triangle<span> APC is a right</span>triangle<span>. The length of CA is 10 m, and the length of PC is 5 m, and hence you can use Pythagoras' theorem to find the length of AP, which </span>is the height<span> of the </span>triangleABC.
Answer:
I believe 1.) is x=y-4/2 and 2.) x=y-4/2 as well
Step-by-step explanation:
1.)
y=2x+4
-subtract 4 on both sides-
y-4=2x
-divide 2 on both sides-
x=y-4/2
2.)
y=2(x+2)
-distribute the 2-
y=2x+2
-subtract 2 on both sides-
y-2=2x
-divide 2 on both sides-
x=y-2/4
I dont know exactly if this is correct, but i hope it helps! :)
We are basically given most of what we need to calculate the height of the cannonball.
We use the formula h = –16t+ vt + s to find the height requested.
Let v = 160
Let s = 10
Let t = time in seconds
Was the value of t included? We need to know t to plug into our formula.
You know everything else except for t. Go back to your notes to search for t. Afterward, plug the value of t and everything else given above into the formula and calculate to find h.
