Which expressions are equivalent to 6 + 12x
1 answer:
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The complete question in the attached figure
we know that
(see the attached figure n 2 to understand the problem)
[the surface area of one prism]=2*[x*x]+2*[x*y]+2*[x*y]----> 2x²+4xy
[the surface area of the sculpture]=2*[5*x*y]+2*[3*x*x]+2*[3*x*y]--> 6x²+16xy
now
<span>JD says the surface area of the sculpture is 4 times the surface area of one prism
</span>[the surface area of the sculpture]=4*(2x²+4xy)---> 8x²+16xy
we compare the value that JD says with the real value
(8x²+16xy) > (6x²+16xy)
the value that JD says is <span>greater in comparison with the real value
</span>This is because <span>JD should also subtract the areas of eight hidden surfaces.
the answer is
</span>JD should also subtract the areas of eight hidden surfaces<span>
</span>
we know that
(see the attached figure n 2 to understand the problem)
[the surface area of one prism]=2*[x*x]+2*[x*y]+2*[x*y]----> 2x²+4xy
[the surface area of the sculpture]=2*[5*x*y]+2*[3*x*x]+2*[3*x*y]--> 6x²+16xy
now
<span>JD says the surface area of the sculpture is 4 times the surface area of one prism
</span>[the surface area of the sculpture]=4*(2x²+4xy)---> 8x²+16xy
we compare the value that JD says with the real value
(8x²+16xy) > (6x²+16xy)
the value that JD says is <span>greater in comparison with the real value
</span>This is because <span>JD should also subtract the areas of eight hidden surfaces.
the answer is
</span>JD should also subtract the areas of eight hidden surfaces<span>
</span>
Answer: The tangent of the larger acute angle is 4/3 or 1⅓
Step-by-step explanation: if the sides of the right angled triangle are given as 3, 4 and 5 respectively, then the hypotenuse is 5 and the longer of the other two sides is 4. The angle facing the side measuring 4 is your reference angle, and that is the larger of the other two acute angles (see attachment)
Tan X = opposite/hypotenuse
Tan X = 4/3
Tan X = 1⅓
