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3 years ago

Please help with this problem

Mathematics

1 answer:

lawyer [7]3 years ago

7 0

Answer:

624

Step-by-step explanation:

Plug into the formula, SA=bh+(s1+s2+s3)H.

H=14

s1=13

s2=13

s3=10

Hope that helps!

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Suppose an automotive repair company wants to determine the current percentage of customers who keep up with regular vehicle mai

Nina [5.8K]

Answer: 1692

Step-by-step explanation:

Formula to find the sample size :

$n=p(1-p)(\dfrac{z_{\alpha/2}}{E})^2$

Given : Confidence level : $(1-\alpha)=0.90$

⇒ significance level = $\alpha= 0.10$

z-value for 90% confidence interval (using z-table)= $z_{\alpha/2}=1.645$

Prior estimate of the population proportion (p) of customers who keep up with regular vehicle maintenance is unknown.

Let we take p= 0.5

Margin of error : E= 2%=0.02

Now, the required sample size will be :

$n=0.5(1-0.5)(\dfrac{1.645}{0.02})^2$

Simplify , we get

$n=(0.25)(6765.0625)=1691.265625\approx1692$

Hence, the required sample size = 1692

8 0

3 years ago

Read 2 more answers

Can you help Jorge organize the results into a two-way frequency table? Please answer this ASAP

Juliette [100K]

Answer:

The table is attached!

Step-by-step explanation:

6 students play both musical instrument and a sport
3 students play neither a musical instrument nor a sport
14 students in total play a sport

Given: There are 24 students in the class

The number of students that does not play a sport is 24 - 14 = 10

The number of students that does not play a musical instrument but play a sport = 14 - 6 = 8

The frequency table thus is attached below:

6 0

3 years ago

Interger for 6(-7) + (-8).

timama [110]

6 multiplied by negative 7 would be negative 42. Negative 42 added by negative 8 would be negative 34.

5 0

3 years ago

Please help me solve this angle problem. It is due today!

Paul [167]

Answer: B
No explanation

7 0

3 years ago

a major metroplitan newspaper selected a simple random sample of 1,600 readers from their list of 100,000 subscribers. they aske

Arisa [49]

Answer:

The 99% confidence interval for the proportion of readers who would like more coverage of local news is (0.3685, 0.4315).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

$n = 1600, \pi = 0.4$

99% confidence level

So $\alpha = 0.01$ , z is the value of Z that has a pvalue of $1 - \frac{0.01}{2} = 0.995$ , so $Z = 2.575$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4 - 2.575\sqrt{\frac{0.4*0.6}{1600}} = 0.3685$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4 + 2.575\sqrt{\frac{0.4*0.6}{1600}} = 0.4315$

The 99% confidence interval for the proportion of readers who would like more coverage of local news is (0.3685, 0.4315).

7 0

3 years ago