Answer:
(3x+4)(5x+7)
Step-by-step explanation:
15x^2
+41x+28
Factor the expression by grouping. First, the expression needs to be rewritten as 15x^2
+ax+bx+28. To find a and b, set up a system to be solved.
a+b=41
ab=15×28=420
Since ab is positive, a and b have the same sign. Since a+b is positive, a and b are both positive. List all such integer pairs that give product 420.
1,420
2,210
3,140
4,105
5,84
6,70
7,60
10,42
12,35
14,30
15,28
20,21
Calculate the sum for each pair.
1+420=421
2+210=212
3+140=143
4+105=109
5+84=89
6+70=76
7+60=67
10+42=52
12+35=47
14+30=44
15+28=43
20+21=41
The solution is the pair that gives sum 41.
a=20
b=21
Rewrite 15x^2
+41x+28 as (15x^2
+20x)+(21x+28).
(15x^2
+20x)+(21x+28)
Factor out 5x in the first and 7 in the second group.
5x(3x+4)+7(3x+4)
Factor out common term 3x+4 by using distributive property.
(3x+4)(5x+7)
Answer:
Claim is false
Step-by-step explanation:
Claim : A credit reporting agency claims that the mean credit card debt in a town is greater than $3500.
n = 20
Since n <30
So we will use t test
Formula : 
s = standard deviation = 391
x = 3600
n = 20
Degree of freedom = n-1 = 20-1 = 19
α=0.10
So, using t table
= 1.72
t critical > t calculated
So we accept the null hypothesis
Hence we reject the claim that the mean credit card debt in a town is greater than $3500.
I'm not sure I'm understanding the wording of the question, but if it's this:
Juice boxes come in a package with multiple juice boxes in each package. Three people bought 18, 36, and 45 juice boxes. What is the largest possible number of juice boxes per package?
Then the problem is just an involved way of asking what the greatest common factor of 18, 36, and 45 is, and the answer is 9, the difference between 36 and 45, which are both multiples of 9. Note that 18 is also a multiple of 9. One way to find the greatest common factor of three numbers is to factor all of them and find which prime factors they have in common.
Answer:
6 lines of symmetry
Step-by-step explanation:
This is a 6 sided polygon which is known as hexagon.
Now, line of symmetry of this hexagon is a line that passes through the centre of it and thereby divides it into equal parts.
Now, we can see the short lines on each side of the hexagon. When they are extended to join a similar line on the opposite face, they all pass through the centre.
Thus, there are
