The area of an equilateral triangle of side "s" is s^2*sqrt(3)/4. So the volume of the slices in your problem is
(x - x^2)^2 * sqrt(3)/4.
Integrating from x = 0 to x = 1, we have
[(1/3)x^3 - (1/2)x^4 + (1/5)x^5]*sqrt(3)/4
= (1/30)*sqrt(3)/4 = sqrt(3)/120 = about 0.0144.
Since this seems quite small, it makes sense to ask what the base area might be...integral from 0 to 1 of (x - x^2) dx = (1/2) - (1/3) = 1/6. Yes, OK, the max height of the triangles occurs where x - x^2 = 1/4, and most of the triangles are quite a bit shorter...
Answer:
Step-by-step explanation: 5/10=1/2 - if one student are chosen, who plays soccer
4/9 if then the second student are chosen, who plays soccer
1/2*4/9=2/9 the probability that both students play soccer
Answer:
8√21
Step-by-step explanation:
A rectangle has 2 congruent pairs. Those 2 pairs are ST/RU and SR/UT. If that is the case, then that means UV is 5 and SV is also 5. Now we have triangle SRU with a hypotenuse of 10 and a side of 4. Pythagorean Theorem:
4² + b² = 10²
b² = 84
b = 2√21
Segment SR is then equal to b. Now we move on to the area formula:
(2√21)(4) = 8√21
And that is your final answer.
I got B and D, sorry if my answers are wrong!!
